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victus00 [196]
3 years ago
11

Find the total surface area of this triangular prism. 30 cm 18 cm 7 cm 24 cm

Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer: <em>936 cm²</em>

Step-by-step explanation:

<em>A = (18 × 24 × 0.5) × 2 + (18 + 30 +24) × 7 = 936 (cm²)</em>

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1. A rectangle with length 9 cm and width 3 cm.<br> What’s the perimeter?
slega [8]

Answer:

24 centimeters

9 cm + 9 cm + 3 cm + 3 cm = 24 cm

l + l + w + w

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3 years ago
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Find the missing side of the triangle. Round to the nearest tenth.
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5.5 because In front of a 30 degree angle is a cathete of half of Hypotenuse.
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Wyatt earns $19.65 per hour and double time for overtime. If he worked his regular schedule of 20 hours and 5 hours of overtime,
andrew-mc [135]

Answer:

$196.50

Step-by-step explanation:

19.65 x 2 = 39.30

He gets $39.30 per hour for overtime. He does over time for 5 hours.

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3 years ago
A statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty w
bulgar [2K]

Answer:

The null and alternative hypothesis are:

H_0: \mu_X-\mu_Y=0\\\\H_a:\mu_X-\mu_Y> 0

P-value=0.1996

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean score μX on one-tailed hypothesis test questions is higher than the mean score μY on two-tailed hypothesis test questions .

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the mean score μX on one-tailed hypothesis test questions is higher than the mean score μY on two-tailed hypothesis test questions .

Then, the null and alternative hypothesis are:

H_0: \mu_X-\mu_Y=0\\\\H_a:\mu_X-\mu_Y> 0

The significance level is 0.05.

The sample X (one-tailed), of size nX=80 has a mean of 7.8 and a standard deviation of 1.06.

The sample Y (two-tailed), of size nY=80 has a mean of 7.64 and a standard deviation of 1.32.

The difference between sample means is Md=0.16.

M_d=M_X-M_Y=7.8-7.64=0.16

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_X^2+\sigma_Y^2}{n}}=\sqrt{\dfrac{1.06^2+1.32^2}{80}}\\\\\\s_{M_d}=\sqrt{\dfrac{2.866}{80}}=\sqrt{0.036}=0.189

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_X-\mu_Y)}{s_{M_d}}=\dfrac{0.16-0}{0.189}=\dfrac{0.16}{0.189}=0.8453

The degrees of freedom for this test are:

df=n_1+n_2-1=80+80-2=158

This test is a right-tailed test, with 158 degrees of freedom and t=0.8453, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>0.8453)=0.1996

As the P-value (0.1996) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean score μX on one-tailed hypothesis test questions is higher than the mean score μY on two-tailed hypothesis test questions .

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3 years ago
Circle the correct answer choice.
Rudiy27

Answer: D) 0.392

Step-by-step explanation:

0.300

0.090

0.002

__________

0.392

6 0
4 years ago
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