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Katarina [22]
4 years ago
12

What’s the most abundant isotope of lawrencium

Chemistry
2 answers:
ale4655 [162]4 years ago
8 0
Lawrencium has 10 recognized isotopes. Its most stable is 262Lr, with a half-life of about four hours.
ch4aika [34]4 years ago
7 0

Answer:

266Lr

Thirteen isotopes of lawrencium are currently known; the most stable is 266Lr with a half-life of 11 hours, but the shorter-lived 260Lr (half-life 2.7 minutes) is most commonly used in chemistry because it can be produced on a larger scale.

Explanation:

hopefully that helps you

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an alien civilization has different names and symbols for six elements. place each element in the correct location in the period
Rina8888 [55]

Answer:

All you have to do is count the number of electrons in the shells and place them according to the atomic number. I just did it.

Explanation:

7 0
3 years ago
In the diagram, which of the following represents the activation energy?
Irina-Kira [14]
Can you post the diagram?
8 0
3 years ago
What makes an atom a good conductor?
andrew-mc [135]
Very little electric force is required to cause electron flow in conductors. This is due to electrons called "free electrons", which exist in the atoms of conductors. "Free electrons" are electrons that are very weakly bonded to the atom. ... Metals such as copper, silver, and gold are good conductors.

Well, atoms are loosely bound and free to move through the material. Almost all, or just most, atoms will hold on to electrons very tightly and are insulators.
3 0
4 years ago
What is Le chatelier's principle?​
ser-zykov [4K]

Answer:

Le Chatelier's principle, also called Chatelier's principle or "The Equilibrium Law", is a principle of chemistry used to predict the effect of a change in conditions on chemical equilibria.

hope it helps ,pls mark me as brainliest

7 0
3 years ago
What is the overall cell potential for this redox reaction? Cd + Hg22+ → Cd2+ + 2Hg Given: Cd2+ + 2e− → Cd(s) = –0.40 and Hg22+
Hoochie [10]

Answer:  1.19 V

Explanation:

Standard potential for an electrochemical cell is given by:

E^0{cell} = standard electrode potential =E^0{cathode}-E^0{anode}

The E^0 values have to be reduction potentials.  

Given:

E^o_{Cd^{2+}/Cd}=-0.40V

E^o_{Hg_2^{2+}/Hg}=0.79V

Cd+Hg_2^{2+}\rightarrow Cd^{2+}+2Hg

Cadmium is losing electrons , undergo oxidation and thus act as anode. mercury is gaining electrons, undergo reduction and thus acts as cathode.

E^0{cell} = standard electrode potential =E^0{cathode}-E^0{anode}=0.79-(-0.40)=1.19V

Thus the standard potential for an electrochemical cell with the cell reaction is 1.19 V.

4 0
3 years ago
Read 2 more answers
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