Question

Need help. Have to finish this today!!!!

Answer 1

Answer:

Step-by-step explanation:

1)a ) Let the constant proportionality =k

Direct proportion.So, y = kx

Plugin y = 6 and x =2 and find k

6 = k*2

6/2 = k

k = 3

Constant proportionality = 3

b)  y = 3x

When x = 7  ; y = 3*7 = 21

y = 21

c)When x = 9,

y = 3*9

y = 27

d) When y = 9,

9 = 3*x

9/3 = x

x = 3

e)when y = 30

30 = 3*x

30/3 =x

x = 10

3) y is inversely proportion to x³

$y =k\dfrac{1}{x^{3}}\\\\3 =k *\dfrac{1}{2^{3}}\\\\3=k*\dfrac{1}{8}\\\\3*8=k\\\\24 = k$

b)  when x = 4

$y=24*\dfrac{1}{4*4*4}\\\\y=\dfrac{3}{8}$

c) When x = 6

$y = 24*\dfrac{1}{6*6*6}\\\\y=\dfrac{1}{9}$

d) When y = 24

$24= 24*\dfrac{1}{x^{3}}\\\\x^{3}*24=24\\\\x^{3}=\dfrac{24}{24}\\\\x^{3}=1\\\\x = 1$