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Andrews [41]
3 years ago
10

What is 5/18 + (-1/6) A.4/9 B.1/9 C.1/3 D.2/3help please!

Mathematics
2 answers:
Vlada [557]3 years ago
4 0
5/18+(-1/6)=1/9                Hope it helps!
slava [35]3 years ago
3 0
It's B.1/9 
Hope this helps.:)
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<img src="https://tex.z-dn.net/?f=solve%20for%20%22m%22%20t%3D%5Cfrac%7Bms%7D%7Bm%2Bn%7D" id="TexFormula1" title="solve for &quo
dalvyx [7]

Answer:

\boxed{\sf \ \ \ m = -\dfrac{tn}{t-s} \ \ \ }

Step-by-step explanation:

Hello,

let s assume that m+n is different from 0

we have this equation and we need to find m as a function of t, s, and n

t=\dfrac{ms}{m+n}

<=>

(m+n)*t=ms\\\\ tm+tn=sm\\ (t-s)m = -tn\\ m = -\dfrac{tn}{t-s}

for t-s different from 0, so t different from s

hope this helps

4 0
3 years ago
If f Superscript negative 1 Baseline (x) = negative one-fifth x, what is f Superscript negative 1 Baseline (x) = one-fifth x?
Artyom0805 [142]

Answer:

  a different inverse function

Step-by-step explanation:

If f^{-1}(x)=-\frac{1}{5}x then f^{-1}(x)=\frac{1}{5}x is a different inverse function.

__

The second (inverse) function is the first reflected over the y-axis.

5 0
3 years ago
Read 2 more answers
I WILL GIVE BRAINLIEST!!!!!!
katovenus [111]

Answer:

I think Quadrant 1. I;m not trying to just answer for the points

Step-by-step explanation:

5 0
3 years ago
-5x+10&gt;-15 help please
nexus9112 [7]

Answer:

Step-by-step explanation:

-5x + 10 > -15 is your original equation.

You need to isolate the x variable.

Start by subtracting 10.

-5x > -25

x > 5

3 0
3 years ago
Which four inequalities can be used to find the solution to this absolute value inequality?
natita [175]

The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the inequality:

3 ≤ |x + 2| ≤ 6

Hence:

x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)

This gives:

x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

Find out more on equation at: brainly.com/question/2972832

#SPJ1

6 0
2 years ago
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