The circle with center (h, k) and radius r has equation
.. (x -h)^2 +(y -k)^2 = r^2
You have
.. h = 2
.. k = 0
.. r = √5
The center is (h, k) = (2, 0).
Answer:
Mr. Chang will have 15714.90 dollars.
Step-by-step explanation:
p = 650
r = 
Number of periods or n = 
Future value formula is : ![p[\frac{(1+r)^{n}-1}{r} ]](https://tex.z-dn.net/?f=p%5B%5Cfrac%7B%281%2Br%29%5E%7Bn%7D-1%7D%7Br%7D%20%5D)
Putting the values in formula we get;
![650[\frac{(1+0.0195)^{20}-1}{0.0195} ]](https://tex.z-dn.net/?f=650%5B%5Cfrac%7B%281%2B0.0195%29%5E%7B20%7D-1%7D%7B0.0195%7D%20%5D)
= $15714.90
Hence, Mr. Chang will have 15714.90 dollars.
There are 18 students in Grade 7, 10 are in band, so 10/18 = 0.56 are in band.
There are 12 students in Grade 8, 10 are in band, so 10/12 = 0.83 are in band.
Students in Grade 8 are more likely to be members of the band.
Answer:
sec(B)=b. ab/bc
sin(B)=c. ac/ab
csc(B)=f. ab/ac
cot(B)=a. bc/ac
tan(B)=e. ac/bc
cos(B)=d. bc/ab
Step-by-step explanation:
<u><em>SOHCAHTOA</em></u>
<u><em>Sine=Opposite/Hypotenuse</em></u>
<u><em>Cosine=Adjacent/Hypotenuse</em></u>
<u><em>Tangent=Opposite/Adjacent</em></u>
<u><em>SHACHOCotAO</em></u>
<u><em>Secant=Hypotenuse/Adjacent</em></u>
<u><em>Cosecant=Hypotenuse/Opposite</em></u>
<u><em>Cotangent=Adjacent/Opposite</em></u>
<u><em /></u>
