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2 years ago

15

Need this answer in the next two minutes please!!!!

1 answer:

Aleks04 [339]2 years ago

8 0

Answer:

D

Step-by-step explanation:

my friend answer this same question the other day

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What is the equation for this line

pogonyaev

The equation of the line is $y=\frac{-1}{5} x-\frac{21}{5}$ .

Solution:

The points on the line are (–6, –3) and (4, –5).

$x_{1}=-6, y_{1}=-3, x_{2}=4, y_{2}=-5$

Slope of the line:

$$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$$m=\frac{-5-(-3)}{4-(-6)}$

$$m=\frac{-5+3}{4+6}$

$$m=\frac{-2}{10}$

$$m=\frac{-1}{5}$

Point-slope formula:

$y-y_{1}=m\left(x-x_{1}\right)$

$$y-(-3)=\frac{-1}{5}(x-(-6))$

$$y+3=\frac{-1}{5}(x+6)$

$$y+3=\frac{-1}{5} x-\frac{6}{5}$

Subtract 3 from both sides of the equation.

$$y=\frac{-1}{5} x-\frac{21}{5}$

The equation of the line is $y=\frac{-1}{5} x-\frac{21}{5}$ .

6 0

3 years ago

Line segment Z E is the angle bisector of AngleYEX and the perpendicular bisector of Line segment G F. Line segment G X is the a

notsponge [240]

i dont l know bro try getting close to God tho

3 0

3 years ago

How many inches are in 13 feet

Dmitriy789 [7]

156 inches are in 13 feet

4 0

3 years ago

Read 2 more answers

You pick a card at random, put it back, and then pick another card at random. 2 3 4 5 What is the probability of picking a numbe

olga_2 [115]

Answer:

3/4 or a 75% chance

Step-by-step explanation:

Out of 4 cards ( 2 3 4 5), here are the cards greater than 3: 4, and 5. That leaves you with a 2/4 chance of drawing one of them. (2 cards, 4 in total).

Then, picking a 4 out of 4 cards is a 1/4 chance; since that is one card out of 4 total possibilities.

1/4 + 2/4 = 3/4. Or, a 75% chance.

3 0

2 years ago

Read 2 more answers

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

$u=x$ $dv=e^(2x)\cdot{dx}$

$du=dx$ $v=2\cdot{e^(2x)}$

$\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du$

$\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx$

$\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C$

We can therefore determine that if x tends to 0 the limit is -1

$\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1$

5 0

3 years ago