Answer:
Step-by-step explanation:
we know that
1 kg=1,000 g
so
using proportion
Find out how many kilograms are 69 grams
Let
x -----> the weight in kg
Answer:
"number line with open circles on negative 9 and 5, shading going in the opposite directions."
Step-by-step explanation:
Your inequality doesn't include an equal sign so there will be no closed holes. It will only be open holes.
|u|>14 means that the number u has to be greater than 14 or less than -14. These numbers I describe just now all have a distance greater than 14 from 0.
So |u|>14 implies u>14 or u<-14.
But we are solving |2x+4|>14 so this implies we have 2x+4>14 or 2x+4<-14.
2x+4>14
Subtract 4 on both sides:
2x >10
Divide both sides by 2:
x >5
2x+4<-14
Subtract 4 on both sides:
2x <-18
Divide both sides by 2:
x <-9
So our solution is x>5 or x<-9.
Graphing!
~~~~~~~O O~~~~~~~~
-----------(-9)---------------------------------(5)---------------
So we shaded to the right of 5 because our inequality says x is bigger than 5.
We shaded to the left of -9 because our inequality says x is less than -9.
To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.
subtract 1 from 3
3-1=2
So each number is having 2 added to it.
Now add two to 7 and the numbers afterwards till you get the 12th term
7+2=9
1+3+5+7+9
9+2=11
1+3+5+7+9+11
11+2=13
1+3+5+7+9+11+13
13+2=15
1+3+5+7+9+11+13+15
15+2=17
1+3+5+7+9+11+13+15+17
17+2=19
1+3+5+7+9+11+13+15+17+19
19+2=21
1+3+5+7+9+11+13+15+17+19+21
21+2=23
1+3+5+7+9+11+13+15+17+19+21+23
So 23 is the 12th term
Answer:
1/14
Step-by-step explanation:
1 - 5/7 = 7/7 - 5/7 = (7-5)/7
Subtract. 7 - 5 = 2
= 2/7
Now we have to multiply 2/7 and 1/4
We get 2/7 x 1/4 = <em>1/14</em>
In general, the volume
has total derivative
If the cylinder's height is kept constant, then
and we have
which is to say,
and
are directly proportional by a factor equivalent to the lateral surface area of the cylinder (
).
Meanwhile, if the cylinder's radius is kept fixed, then
since
. In other words,
and
are directly proportional by a factor of the surface area of the cylinder's circular face (
).
Finally, the general case (
and
not constant), you can see from the total derivative that
is affected by both
and
in combination.
