Answer:
I think its letter d........
Answer:
Chemically gated Na+-K+ channels
Explanation:
The acetylcholine receptors are the receptors or ion channel proteins which are considered the transmembrane proteins. The acetylcholine receptors are of two types depending on the ligand which binds that is either nicotinic or either muscarinic receptors.
When the acetylcholine binds the receptor molecule, the ion channels open up and allows the passage of the sodium and potassium ios which depolarizes the membrane potential and generates the action potential in the neuron.
Thus, Chemically gated Na+-K+ channels is correct.
Answer:
1. True
Biotic factors can have effect on abiotic factors like water by the way they use it and how much they drink. If biotic factors drink too much water in a rivver then it could end up with limited amount of water for the ecosystem.
2. False
On average, about 50 percent of energy available within one trophic level is transferred to the next trophic level.
3. True
Extirpation is extinction of a species in a given area.
The answer is 0.47 or 47%.
Let's first distinguish some terms and their frequencies.
R - the dominant allele that causes red eyes
r - the recessive allele that causes green eyes
Since R is dominant over r, lizards with at least one dominant R allele will have red eyes. Therefore, the genotypes and the phenotypes are as following:
genotypes - phenotypes
RR - the lizards with red eyes
Rr - the lizards with red eyes
rr - the lizards with green eyes
Now, we will use some Hardy-Weinberg equations:
p + q = 1
p² + 2pq + q² = 1
where:
p - the frequency of dominant allele R
q - the frequency of recessive allele r
p² - the frequency of lizards with genotype RR
2pq - the frequency of lizards with genotype Rr
q² - the frequency of lizards with genotype <span>rr
</span>
We are interested in <span>the frequency p of the dominant R allele.
</span>So, we have the frequency (72%) of the lizards that have red eyes. However, lizards with genotypes RR and Rr will have red eyes. Since their frequencies are p² and 2pq, respectively, we have:
p² and 2pq = 72% = 72/100 = 0.72
Now, use this in the equation p² + 2pq + q² = 1:
0.72 + q² = 1
q² = 1 - 0.72 = 0.28
From here, we will calculate q and later p using the formula p + q = 1:
q² = 0.28
q = √0.28 = 0.53
p + q = 1
p + 0.53 = 1
p = 1 - 0.53
p = 0.47
