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trasher [3.6K]
4 years ago
7

Jane addresses twice as many envelopes as Louis in the same amount of time. Together they address 420 envelopes each day. How ma

ny envelopes does Jane address in a day?
Mathematics
2 answers:
Solnce55 [7]4 years ago
7 0
She addresses 280 envelopes while Louis addresses only 140.
OlgaM077 [116]4 years ago
5 0

Step-by-step explanation:

Louis addresses x envelopes = x

Jane addresses (2 × x) envelopes = 2x

Total envelopes daily = 420 envelopes

x + 2x = 420

3x = 420

x = 420/3

x = 140

Jane addresses 2 × x = 2 ×140 = 280 envelopes

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Pls help! I need to know if this is right! 50 points!
Sedaia [141]

Answer: B) (x-1)2+(y+1)2= 25 radius = 5 miles

Step-by-step explanation:

In order to get this answer you see that you are adding a negative to x in the first part then multiplying it by 2. Second, you add y+1 then multiplying it by 2. You get the radius of 25 which equals 5 miles. Look at the graph to also check your answers to the problem.

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4 years ago
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1,3,2,6,3,9,4,12... what will be the eleventh number in the pattern?
katrin [286]

Answer:

11th number is 6

Step-by-step explanation:

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1 year ago
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If each foot of water in a lake screens out 60% of the light above, what percent of the light passes through 5 feet of water?
BartSMP [9]
The amount of light passing through each foot the water in the lake = 100% - 60% = 40%
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8 0
3 years ago
Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con
Ket [755]

Answer:

Step-by-step explanation:

Given that:

H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }

Z = \dfrac{-1}{\dfrac{5.3}{6} }

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

b

For x = 53 and s = 4.6

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }

Z = \dfrac{-2}{\dfrac{4.6}{6} }

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

Conclusion: \  There  \ is \  sufficient \  evidence  \  to \  conclude \  that \mu < 55

c)

For x = 56 and s = 5.0

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

6 0
3 years ago
I need the equation and steps please!
serg [7]
Let d is the number of days of rental car
At Trinity's Tire World, $50 a day plus $75 fee: 50*d + 75
At India's Auto,  $35 a day plus $105 fee: 35*d + 105

To find out after how many days, they both cost the same

50*d + 75 = 35*d + 105
50d + 35d = 105 - 75
15d = 30
d = 30/15
d = 2

Answer: after 2 days, they both cost the same amount of money

Proof:

50*d + 75 = 50*2 + 75 = 100 + 75 = 175
35*d + 105 = 35*2 + 105 = 70 + 105 = 175

Hope that helps

3 0
3 years ago
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