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Ratling [72]
3 years ago
12

How would i do this problem?

Mathematics
2 answers:
Darya [45]3 years ago
6 0

Answer:

answer is a=22

follow me!

CaHeK987 [17]3 years ago
5 0

Answer:

a=22 hope it helps:))

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In △ABC, m∠A=16°, m∠B=49°, and a=4. Find c to the nearest tenth.<br><br><br> NOT A RIGHT TRIANGLE
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Answer:

c = 13.2

Step-by-step explanation:

* Lets explain how to solve the problem

- In Δ ABC

# Side a is opposite to ∠A

# Side b is opposite to ∠B

# Side c is opposite to ∠C

- The sine rule is:

# \frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}

* Lets solve the problem

- In Δ ABC

∵ m∠A = 16°

∵ m∠B = 49°

∵ The sum of the measures of the interior angles of a triangle is 180°

∴ m∠A + m∠B + m∠C = 180°

∴ 16° + 49° + m∠C = 180°

∴ 65° + m∠C = 180° ⇒ subtract 65° from both sides

∴ m∠C = 115°

- Lets use the sine rule to find c

∵ a = 4 and m∠A = 16°

∵ m∠C = 115°

∵ \frac{4}{sin(16)}=\frac{c}{sin(115)}

- By using cross multiplication

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∴ c=\frac{4(sin115)}{sin16}=13.2

* c = 13.2

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a

Step-by-step explanation:

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