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Sliva [168]
3 years ago
13

Consider the following literal equation.

Mathematics
1 answer:
galina1969 [7]3 years ago
4 0

We can solve this in many ways, let's try this one.

T∧2 = 4 pi∧2 * a∧3 / GM    First we will multiply whole equation with variable( or parameter) M and get

M * T∧2 = 4 pi∧2 * a∧3 / G  After that we will divide whole equation with variable ( or parameter )  T∧2 and get

M = 4 pi∧2 * a∧3 / G * T∧2

This is correct answer

Good luck!!!

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Please help. 21 points
Eduardwww [97]

Answer:

4/5 ÷3/5

4/5×5/3(any time one is dividing a fraction, the dominator would go up while the numerator would come down).

=4/3

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3 years ago
Write a exspession for 8 divided by d
BlackZzzverrR [31]

Answer:

8/D

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2 years ago
What is the meaning of numerical form?
kozerog [31]
Numerical form is an actual number as opposed to a word. 

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Ten times as many as 100 is
mrs_skeptik [129]
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3 years ago
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If it took Carlos 30 minutes to cycle from his house to the library yesterday, was the distance that he cycled greater than 6 mi
Ivanshal [37]

Answer:

1) No

2) Yes

Step-by-step explanation:

Given : If it took Carlos 30 minutes to cycle from his house to the library yesterday.

To find : Was the distance that he cycled greater than 6 miles?

Solution :

The relation between speed , distance and time is

\text{Distance}=\text{Speed}\times \text{Time}

1) The average speed at which Carlos cycled from his house to the library yesterday was greater than 16 feet per second.

Speed = 16 feet per second

Converting into miles, s=\frac{16}{5280}

Time = 30 minute

Converting into seconds, t=30\times 60

The distance he covered is

\text{Distance}=\frac{16}{5280}\times30\times 60

\text{Distance}=5.45\text{ miles}

No, the distance that he cycled is not greater than 6 miles.

2) The average speed at which Carlos cycled from his house to the library yesterday was less than 18 feet per second.

Speed = 18 feet per second

Converting into miles, s=\frac{18}{5280}

Time = 30 minute

Converting into seconds, t=30\times 60

The distance he covered is

\text{Distance}=\frac{18}{5280}\times30\times 60

\text{Distance}=6.13\text{ miles}

Yes, the distance that he cycled is greater than 6 miles.

6 0
3 years ago
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