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Sliva [168]
2 years ago
13

Consider the following literal equation.

Mathematics
1 answer:
galina1969 [7]2 years ago
4 0

We can solve this in many ways, let's try this one.

T∧2 = 4 pi∧2 * a∧3 / GM    First we will multiply whole equation with variable( or parameter) M and get

M * T∧2 = 4 pi∧2 * a∧3 / G  After that we will divide whole equation with variable ( or parameter )  T∧2 and get

M = 4 pi∧2 * a∧3 / G * T∧2

This is correct answer

Good luck!!!

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HELPPPP!!!
Hatshy [7]

Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

- Lets make (x² - 2x) completing square

∵ √x² = x

∴ The 1st term in the bracket is x

∵ 2x ÷ 2 = x

∴ The product of the 1st term and the 2nd term is x

∵ The 1st term is x

∴ the second term = x ÷ x = 1

∴ The bracket is (x - 1)²

∵  (x - 1)² = (x² - 2x + 1)

∴ To complete the square add 1 to the bracket and subtract 1 out

   the bracket to keep the equation as it

∴ (x² - 2x + 1) - 1

- We will do the same withe bracket of y

- Lets make 4(y² - 4y) completing square

∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

∴ the second term = 2y ÷ y = 2

∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

   the bracket to keep the equation as it

∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

∴ (x - 1)² - 4(y - 2)² = 16 ⇒ divide both sides by 16

∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

   (x - 1)²/4² - (y - 2)²/2² = 1

4 0
3 years ago
How to do this? pls don't ignore
oksano4ka [1.4K]
So basically you just need to do the Pythagorean theorem to find the sides of the shaded rectangle, with c being the length of the side.

Small side:
2^2 + 6^2 = c^2
4 + 36 = c^2
40 = c^2
C is similar to 6.32456

Long side:
12^2 + 4^2 = c^2
144 + 16 = c^2
160=c^2
C is similar to 12.64911

And then you just multiply!

7 0
2 years ago
Read 2 more answers
When d the product of 6 and 6 is divided by the sum of 6 and 6 what is the quotient? Explain.
shepuryov [24]
Hope it helps! If it is, Brainliest please!

7 0
2 years ago
Read 2 more answers
Enter the correct answer in the box. Write your answer in the form y = mx + b, using the appropriate inequality symbol in place
Dennis_Churaev [7]

Answer:

y ≥ -x - 4

Step-by-step explanation:

\sf let (x_1,y_1)=(-4,0)\\\\let (x_2,y_2)=(0,-4)

\sf slope \ (m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-4-0}{0-(-4)}=-1

Slope-point form of linear equation:

\sf \implies y-y_1=m(x-x_1)

\sf \implies y-0=-1(x-(-4))

\sf \implies y=-x-4

For ≤ or ≥ graph a solid line

For < or > graph a dashed line

For shading above the line: y ≥ or y >

For shading below the line:  y ≤ or y <

Therefore, as the line is solid and shading is above the line:

\sf y\geq -x-4

7 0
2 years ago
How do you make 95 into a decimal
aleksklad [387]
To make 95 into a decimal, you can just put a decimal point in front of the number because it is out of 100. So your answer would be .95
3 0
3 years ago
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