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2 years ago

Solve each equation by factoring.

Mathematics

1 answer:

nevsk [136]2 years ago

4 0

Answer:

k=1/3; k=-2/5

Step-by-step explanation:

$15k^2+k-4=-2\\15k^2+k-2=0\\(3k-1)(5k+2)=0\\3k-1=0; 5k+2=0\\k=1/3; k=-2/5$

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Based on data collected from its production processes, Crosstiles Inc. determines that the breaking strength of its most popular

alexandr1967 [171]

Answer:

16% of its popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch.

Step-by-step explanation:

We are given that the breaking strength of its most popular porcelain tile is normally distributed with a mean of 400 pounds per square inch and a the standard deviation of 12.5 pounds per square inch.

Let X = the breaking strength of its most popular porcelain tile

SO, X ~ Normal( $\mu=400,\sigma^{2}=12.5^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean breaking strength of porcelain tile = 400 pounds per square inch

$\sigma$ = standard deviation = 12.5 pounds per square inch

Now, probability that the popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch is given by = P(X > 412.5)

P(X > 412.5) = P( $\frac{X-\mu}{\sigma}$ > $\frac{412.5-400}{12.5}$ ) = P(Z > 1) = 1 - P(Z $\leq$ 1)

= 1 - 0.84 = 0.16

Therefore, 16% of its popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch.

7 0

2 years ago

Write an equivalent expression for -6(a+8)

stepan [7]

-6a-48 that would be it because you are only distributing the -6

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2 years ago

Set F1 = 5N at 0 degrees, F2= 5N at 90 degrees, F3 = 5N at 270 degrees and run the simulation. Using trigonometry, what net forc

Mrac [35]

Answer: find the solution in the explanation

Step-by-step explanation:

Let's use resolution of forces by resolving into x - component and y- component.

X - component.

Sum of forces = F1 - F3 - F4cos 15

Sum of forces = 0

5 - 5 - 0.97F4 = 0

- 0.97 F4 = 0

F4 = 0

Y - component

Sum of forces = F2 + F4 sin 15

Sum of forces = 0

5 + 0.26F4 = 0

0.26 F4 = -5

F4 = -5/0.26

F4 = -19.23 N

Simulating F4 back into the equation

Sum of forces = F1 - F3 - F4cos 15

- F4cos Ø = 0

- (-19.23) cos Ø = 0

Cos Ø = 0

Ø = 1

Does the angle formed approximate 15 degrees ? NO

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2 years ago

Find the point-slope equation of the line with slope -3 that passes through the point (2, -10).

MatroZZZ [7]

Answer:

Step-by-step explanation

(-y-y1)/(x-x1)= m

y-(-10)/(x-2)= -3

y= -3x -4

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2 years ago

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What is the distance?

Arlecino [84]

Answer:

.25 it 1/4 or an inch should be correct

5 0

2 years ago