Answer:
The answer to your question is 308.1 g of KmNO₄
Explanation:
Data
Volume = 6 L
Concentration = 0.325 M
Molar mass of Potassium permanganate = 39 + 55 + (16 x 4) = 158 g
Process
1.- Calculate the moles of KMnO₄
Formula
Molarity = moles/volume
moles = molarity x volume
moles = 0.325 x 6
moles = 1.95
2.- Calculate the grams of KMnO₄
158 g KMnO₄ ------------------ 1 mol
x ------------------ 1.95
x = (1.95 x 158)/1
x = 308.1 g
Answer:
Explanation:
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