The anode is the electrode where the oxidation occurs.
Cathode is the electrode where the reducction occurs.
Equations:
Mn(2+) + 2e- ---> Mn(s) Eo = - 1.18 V
2Fe(3+) + 2e- ----> 2 Fe(2+) 2Eo = + 1.54 V
The electrons flow from the electrode with the lower Eo to the electrode with the higher Eo yielding to a positive voltage.
Eo = 1.54 V - (- 1.18) = 1.54 + 1.18 = 2.72
Answer: 2.72 V
Metals naturally form cations.
Na only because cation is a positive ion whole cl is a negative ion in anion
Answer:
C) The most efficient fusion reactors would use heavier forms of hydrogen.
Explanation:
From the information presented to us in the question, the third sentence reveals that heavier forms of hydrogen produces larger amount of energy and most importantly reacts more efficiently when fusion occurs.
<em>In fact, the </em><u><em>heavy isotopes of hydrogen—deuterium and tritium—react more efficiently</em></u><em> with each other, and, when they do undergo fusion, they yield more energy per reaction than do two hydrogen nuclei. </em>
