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3 years ago

Who was the second person to organize the elements on the periodic table and what property did he use to re-organize them?

Chemistry

1 answer:

makkiz [27]3 years ago

8 0

Answer:

Dmitri Mendeleev

Explanation:

He was a Russian Scientist who decided to reorganize the periodic table after other notable scientists such as Antoine-Laurent Lavoisier had also tried to organize it based on the states of matter of the elements.

Mendeleev reorganized the period in the order of increasing atomic mass although there were some other modifications by modern scientists.

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As of right now, which of the following forms of nuclear power is the most feasible for human use?

nikitadnepr [17]

As of now, the nuclear fission is the most feasible energy source for human use. All the nuclear power plants are based on the controlled nuclear fission reaction, where the unstable nucleus is bombarded with high speed neutrons, thus, splitting the nucleus into stable ones and releasing huge amount of energy. The nuclear fusion requires very high temperature, the temperature equal's to that of the sun. Hence, it is not feasible right now. As the technology advances, we will see advancement in other form of energies.

6 0

3 years ago

Read 2 more answers

How many atoms are there in 4.13 moles of nickel (Ni)

PtichkaEL [24]

Answer:

24.87× 10²³ atoms of Ni

Explanation:

Given data:

Number of atoms of Ni= ?

Number of moles of Ni = 4.13 mol

Solution:

we will calculate the number of atoms of Ni by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

4.13 mol × 6.022 × 10²³ atoms /1 mol

24.87× 10²³ atoms of Ni

6 0

3 years ago

You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain

Margarita [4]

Answer: 12

Explanation.

This problem was recently posted and deals with the conversion of units,so I give the same answer.

You need to convert the 9 quibs of skvarnick to sleps, to determine how many sleps you have.

The conversion of units is easily undertaken once you build your conversion factors.

Conversion factors are ratios (fractions) equivalent to one, which permits use the identity property of the multiplication to change one unit to a different equivalent one.

Remember that the identity property of multiplication states that any amount multiplied by 1 remains unchanged, i.e.

$a.1=a$

Then, build your conversion factor from the definitions given:

12 sleps is equal to 9 quibs.

12 sleps = 9 quibs

in virtue of the division property of equality, you can divide both sides by 12 sleps and get:

1 = 12 sleps / 9 quibs ← conversion factor

Now you can multiply the amount 9 quibs by the conversion factor, which is equal to 1, to find the equivalent amount of sleps:

identity property: 9 quibs = 9 quibs × 1

substitution property: 9 quibs = 9 quibs × 12 sleps/ 9 quibs

You can see that the unit quibs appear in the numerator and the denominator so it cancels out, and the result will be in sleps.

So, all you have to do now is the operations with the numbers:

9 quibs = (9 × 12 / 9) sleps = 12 sleps ← answer

3 0

3 years ago

Name four products of incomplete combustion<br><br> 1 - ____<br> 2 -____<br> 3 -____<br> 4 -_____

faltersainse [42]

Answer:

Carbon Monoxide / Carbon Dioxide / Sulfur and Nitrogen Dioxide

Explanation:

3 0

3 years ago

A solution was found to have a 15.6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path le

Gnesinka [82]

For the absorbance of the solution in a 1.00 cm cell at 500 nm is mathematically given as

A’ = 0.16138

<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>

Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069

Generally, the equation for the Beer’s law is mathematically given as

A = ε*c*l

0.8069 = ε*c*(5.00 )

ε*c = 0.16138 cm-1

then for when ε*c is constant

l’ = 1.00

A’ = (0.16138 cm-1)*(1.00 cm)

A’ = 0.16138

In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138