What contribution did J.J. Thomson make to the development of atomic theory?

A compound is 2. 00% H by mass, 32. 7% S by mass, and 65. 3% O by mass. What is its empirical formula? The final step is to use

LekaFEV [45]

The empirical formula of this compound is $H_2SO_4$

Given the following data:

Percentage of H = 2.00%

Percentage of S = 32.7%

Percentage of O = 65.3%

Scientific data:

Molar mass of hydrogen (H) = 1.0 g/mol.

Molar mass of sulfur (S) = 32 g/mol.

Molar mass of oxygen (O) = 16 g/mol.

To determine the empirical formula of this compound:

Note: We would assume that the mass of the compound is 100 grams.

Hence, the mass of its constituent elements are:

Mass of hydrogen (H) = 2.00 grams

Mass of sulfur (S) = 32.7 grams

Mass of oxygen (O) = 65.3 grams

Next, we would determine the number of moles of each element by using this formula:

$Number\;of\;moles = \frac{mass}{molar\;mass}$

For hydrogen (H):

$Number\;of\;moles = \frac{2.00}{1}$

Number of moles = 2.0 moles

For sulfur (S):

$Number\;of\;moles = \frac{32.7}{32}$

Number of moles = 1.0 moles

For oxygen (O):

$Number\;of\;moles = \frac{65.3}{16}$

Number of moles = 4.0 moles

Empirical formula = $H_2SO_4$

3 0

2 years ago

Hurricanes can be very destructive, bringing tornadoes, flooding, strong winds, and storm surges to the land areas they come in

Darina [25.2K]

I think this one is the “a wall of water that is pushed ashore”

4 0

3 years ago

Read 2 more answers

Write the iupac name for the compound below. be sure to use correct punctuation.

CaHeK987 [17]

I can't answer this question if the structural formula is not given. However, I found a similar problem in terms of wording. Taking this problem to be solved, let's take a look at the structural formula as shown in the second picture. First, you must know the parent chain, which is the longest chain. This is a trial-and-error process. The longest chain which has a branching group that is nearest to the head is the correct numbering. In this case, the longest chain has 8 carbon atoms. Thus, the base of the name if octane. Because a 3-carbon chain is branching from the 4th carbon, the IUPAC name of the compound shown is: 4-propyloctane.