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zubka84 [21]
3 years ago
7

What volume of 12.0 M sulfuric acid is needed to prepare 300.0 mL of 2.50 M solution?

Chemistry
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

n=c*V

=2.50*300x10^-3

=.75 moles of hcl

v=n/c

=.75/12

=.0625 L

convert to mL

=62.5mL

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When the volume of a gas is
Cerrena [4.2K]

Answer:

THE NEW VOLUME OF THE GAS IS 406 mL WHEN THE TEMPERATURE CHANGES FROM 765 K TO 315 K.

Explanation:

When the temperature changes from  765 K to 315K, the volume has changed from 986 mL to?

V1 = 986 mL = 0.986 L

T1 = 765 K

T2 = 315 K

V2 = unknown

Using Charles' equation of gas laws;

V1 / T1 = V2 / T2

Making V2 the subject of the formula:

V2 = V1 T2 / T1

V2 = 0.986 * 315 / 765

V2 = 0.406 L

V2 = 406 mL

So therefore, the volume of a gas changes from 986 mL to 406 mL as a result of a change in temperature from 765 K to 315 K.

7 0
3 years ago
to checkt the accuracy of a new method, a standard copper alloy containing 23.24%Cu was analyzed and calculated to contain 23.17
tekilochka [14]

Answer:

23.24%_23.17%

10%×1000

10/100×1000=

100

3 0
3 years ago
A glass holds 6 ounces of 60-proof rum (30 alcohol). how much fruit juice must be added to the rum so that the mixture is dilute
Elenna [48]

We need an equation that will relate the concentrated mixture and the diluted one. To solve this we use the equation, 

M1 V1 = M2 V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

M1V1 = M2V2

30 % x 6 oz = 20 %  x V2

V2 = 9 oz 


The volume of the diluted mixture would be 9 oz. Therefore, you will need to add 9 oz - 6 oz = 3 oz of fruit juice to dilute the 30 percent alcohol to 20 percent alcohol.

7 0
3 years ago
A balloon inflated in a room at 25oC has a volume of 3.00 L. If the balloon is heated at a constant pressure, at what temperatur
Alexeev081 [22]

Answer:

596K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

V1 = 3.00 L

V2 = double of V1 = 2 × 3.00 = 6.00 L

T1 = 25°C = 25 + 273 = 298K

T2 = ?

Using V1/T1 = V2/T2

3/298 = 6/T2

Cross multiply

298 × 6 = 3 × T2

1788 = 3T2

T2 = 1788 ÷ 3

T2 = 596K

8 0
3 years ago
Where do meteorologists obtain the data they use to make a <br> weather forecast?
andre [41]

Answer:

doppler radar, radiosondes, weather satellites, buoys

8 0
3 years ago
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