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vodka [1.7K]
3 years ago
7

I need help on all the questions here

Mathematics
2 answers:
Slav-nsk [51]3 years ago
4 0
They all are all math vocabulary
GuDViN [60]3 years ago
4 0
Yeah they are math vocab. Maybe you have choices or past pages telling you the answers?<span />
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Please help or else your not getting a signed autograph by Shrek!
Vinil7 [7]

Answer:

HERE SHREK TV

Step-by-step explanation:

WWW.HUB.COM

3 0
3 years ago
Convert the following measurements:
satela [25.4K]

Step-by-step explanation:

a.3.4cm

b.23000l

c.0.016g

d.3000m

e.2000mg

4 0
3 years ago
Are 2/5 4/10 6/15 and 8/20 proportional?
Over [174]
Yes, since you can multiply 2/5 numerator and denominator to get the rest of the fractions, it makes them all equivalent.
5 0
3 years ago
Read 2 more answers
A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

4 0
3 years ago
Solve the system of equations by substitution X=-4y X+5y=2​
maw [93]

Answer:

use -4y for x in the second equation

-4 y + 5 y = 2

so

y = 2

then x = -4(2) = -8

(-8 , 2)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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