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3 years ago

I need help on all the questions here

Mathematics

2 answers:

Slav-nsk [51]3 years ago

4 0

They all are all math vocabulary

GuDViN [60]3 years ago

4 0

Yeah they are math vocab. Maybe you have choices or past pages telling you the answers?

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|BRAINLIEST|

Mekhanik [1.2K]

Answer:

the correct answer is C 1/32 Ib

Step-by-step explanation:

hope it helps

3 0

3 years ago

How many solutions does this linear system have? Y=2/3x+2 6x-4y=-10

Vilka [71]

Answer:

It a simultaneous equation so the solution is 2

Step-by-step explanation:

5 0

3 years ago

A greeting card uses a geometric design containing 4 congruent kites. The card is 4 inches wide and 8 inches long. What is the a

Gnom [1K]

Answer: 4 sq. in

Step-by-step explanation:

From the question, the card is 8 inches long. Therefore, the length of the vertical diagonal of 1 kite + the length of the vertical diagonal of other kite = 8

Since we have been told that the kites are congruent, therefore the length of the vertical diagonal of both kites will be thesame

Therefore, 2(length of the vertical diagonal of 1 kite) = 8

Therefore, the length of the vertical diagonal of 1 kite will be= 4 inches

The width of the card = 4 inches

Therefore, the length of the horizontal diagonal of 1 kite + the length of the horizontal diagonal of another kite =4

Since the kites are congruent, therefore, the length of the horizontal diagonal of both kites are the same

Therefore, 2(length of the horizontal diagonal of 1 kite) = 4

Therefore, the length of the horizontal diagonal of 1 kite will be= 2 inches

Therefore, the length of the vertical diagonal of the kite= 4 inches and the horizontal diagonal= 2 inches

So, Area of kite = pq/2

Where p and q are diagonals of kite

Area of kite = (4×2)/2

=8/2

= 4 inches square

3 0

2 years ago

Read 2 more answers

What conic section degenerates into a line?

andrew11 [14]

<h3>Answer: A) parabola</h3>

Some degenerate parabola cases form a single straight line, while other cases form one pair of parallel lines.

A degenerate hyperbola forms two lines that intersect at the vertex of the cone. We can rule out choice B.

A degenerate circle is a single point, so we can rule out choice C.

A degenerate ellipse is also a single point. Any circle is an ellipse (but not the other way around). We can rule out choice D.

5 0

3 years ago

The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,

strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=400$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=80$ represent the population standard deviation

n=15 represent the sample size

2) Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$400-2.58\frac{80}{\sqrt{15}}=346.708$

$400+2.58\frac{80}{\sqrt{15}}=453.292$

So on this case the 99% confidence interval would be given by (346.708;453.292)

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that $t_{\alpha/2}=2.98$

Now we have everything in order to replace into formula (1):

$400-2.98\frac{80}{\sqrt{15}}=338.445$

$400+2.98\frac{80}{\sqrt{15}}=461.555$

So on this case the 99% confidence interval would be given by (338.445;461.555)

4 0

2 years ago