Using the formula: E = kQ / d² where E is the electric field, Q is the test charge in coulomb, and d is the distance.
E = kQ / d²
k = 9 x 10^9 N-m²/C²
Q = 6.4 x 10^-5 C
d = 2.5 x 10^-2 m
Substituting the given values to the equation, we have:
E = (9 x 10^9)(6.4 x 10^-5) / (2.5 x 10^-2) ²
Electric field at the test charge is 921600000 N/C
Answer:
Ecliptic
Explanation:
You asked for the term that is used to describe Earth going around the sun
The ecliptic is the path the sun, moon, and planets take across the sky as seen from Earth. It best defines the plane of the Earth's orbit around the sun. The imaginary line can best be visualized in the days just before full moon.
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Answer: 3.7×10¹²watts
Explanation:
Radiation is one of the mode of heat transfer and modes differs from each other based on their medium of heat transfer. Radiation is a process of transferring heat energy from one point to another without heating the intervening medium (no material medium is required).
According to Stefan's law of radiation, the rate of emission of radiant energy is directly proportional to the fourth power of its absolute temperature.
Mathematically, R = eAT⁴
e is constant of proportionality called emissivity. Emissivity varies depending on the type of body being considered.
For the question, we are considering black body and emissivity of black body is 1 being a perfect body.
A is the area of the body
T is the absolute temperature
e = 1
A = 0.5cm²
T = 1650°C
Rate of radiation = 1×0.5×1650⁴
= 3.7×10¹²watts.
The hole will therefore radiate 3.7×10¹²watts
Explanation:
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