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vodomira [7]
3 years ago
5

Without using a micrometer screw gauge, how do I find the average diameter of a long piece of thin wire using a metre rule and a

uniform glass rod?​
Physics
1 answer:
Mice21 [21]3 years ago
5 0

Answer:

Wind the long piece of thin wire around the uniform glass rod multiple times, find the length of the total diameters using the metre ruler, and divide by the number of times you wound it around the rod.

Explanation:

Since the diameter of one long piece of thin wire is too thin to be measured by a metre ruler, you can wind it multiple times and push it side by side to get a length you can measure.

For example, if you wound it around 20 times and the total length of 20 diameters of the wire side-by-side is 2.0 cm, one winding, which is the diameter would be 2.0cm ÷ 20 = 0.10cm or 1mm.

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Answer:

  1. 20 j or 20 N/m

Explanation:

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If you disconnect the wires from the battery and then reconnect them at the opposite ends of the battery, how does that change t
Likurg_2 [28]

Answer:

Explanation:

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What might happen when the function of the two remaining systems is affected. 1.Digestive System
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Explanation:

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3 years ago
1. What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30 m?
aivan3 [116]

Answer:

1. v = 30 m/s

2. v = 5 m/s

3. f = 40 Hz

4. f = 400 Hz

5. f = 300 Hz

6. λ = 0.772 m

7. λ = 0.386 m

8. λ = 0.625 m

9. v = 100 m/s

10. v = 50 m/s

Explanation:

The relationship between frequency, wavelength, and speed of a wave is given by the following formula:

v = f\lambda

where,

v = speed of wave

f = frequency of wave

λ = wavelength

1.

f = 100 Hz

λ = 0.3 m

Therefore,

v = (100 Hz)(0.3 m)

<u>v = 30 m/s</u>

<u></u>

2.

f = 50 Hz

λ = 0.1 m

v = (50 Hz)(0.1 m)

<u>v = 5 m/s</u>

<u></u>

3.

v = 20 m/s

λ = 0.5 m

f = \frac{v}{\lambda} = \frac{20\ m/s}{0.5\ m}

<u>f = 40 Hz</u>

<u></u>

4.

v = 80 m/s

λ = 0.2 m

f = \frac{v}{\lambda}=\frac{80\ m/s}{0.2\ m}

<u>f = 400 Hz</u>

<u></u>

5.

v = 120 m/s

λ = 0.4 m

f = \frac{v}{\lambda}=\frac{120\ m/s}{0.4\ m}

<u>f = 300 Hz</u>

<u></u>

6.

v = 340 m/s

f = 440 Hz

\lambda = \frac{v}{f}=\frac{340\ m/s}{440\ Hz}\\

<u>λ = 0.772 m</u>

<u></u>

7.

v = 340 m/s

f = 880 Hz

\lambda = \frac{v}{f}=\frac{340\ m/s}{880\ Hz}\\

<u>λ = 0.386 m</u>

<u></u>

<u></u>

8.

v = 250 m/s

f = 400 Hz

\lambda = \frac{v}{f}=\frac{250\ m/s}{400\ Hz}\\

<u>λ = 0.625 m</u>

<u></u>

9.

f = 50 Hz

λ = 2 m

v = (50 Hz)(2 m)

<u>v = 100 m/s</u>

<u></u>

10.

f = 100 Hz

λ = 0.5 m

v = (100 Hz)(0.5 m)

<u>v = 50 m/s</u>

6 0
3 years ago
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