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fomenos
3 years ago
14

A 10.0-L rigid container holds 3.00 mol H2 gas at a pressure of 4.50 atm. What is the temperature of the gas?

Chemistry
1 answer:
prisoha [69]3 years ago
3 0
We can approach this problem using the ideal gas law which is as follows:

PV = nRT

P = pressure
V = volume
n = number of moles
R = gas constant, 0.08206 Latm/Kmol
T = temperature

We are asked to solve for temperature and can rearrange the equation to solve for T:

PV = nRT
T = PV/nR

Now we simply plug in the data to solve for T:

T = (4.50 atm)(10.0 L)/(3.00 mol)(0.08206 Latm/Kmol)
T = 183 K

The temperature of the gas is 183 K.
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Explain why different liquids do not reach the same height in capillary tubes of the same diameter. Please choose the best expla
andrezito [222]

Answer:

c) Cohesive forces stronger than adhesive forces reduce the height of the liquid in the capillary tube, whereas adhesive forces stronger than cohesive forces increase the height of the liquid.

Explanation:

Two types of forces bring about capillary action.

One is <em>cohesion</em><em>, which is the intermolecular attraction between like molecules (that is, the liquid molecules)</em>. The second force, called a<em>dhesion</em><em>, is an attraction between unlike molecules, such as those in a liquid and in the sides of a glass tube.</em>

If adhesion is stronger than cohesion, the contents of the tube will be pulled upward. This process continues until the adhesive force is balanced by the weight of the liquid in the tube.

4 0
4 years ago
A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *
elena-14-01-66 [18.8K]

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (kPa)
  2. P2 = final pressure (kPa)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

Learn more about Boyle's law calculations at: brainly.com/question/1437490?referrer=searchResults

3 0
3 years ago
Which of the following statements is most accurate?
Anvisha [2.4K]

Answer:

the option is option(J)

7 0
3 years ago
Exactly 313.5 J will raise the temperature of 10.0 g of a metal from 25.0 C to 60.0 C. What is the specific heat of the metal?
torisob [31]
From the equation Q = m\cdot c_e\cdot \Delta T we can clear specific heat:

c_e = \frac{Q}{m\cdot \Delta T}\ \to\ c_e = \frac{313.5\ J}{10\ g\cdot (60 - 25)^\circ C} = \bf 0.896\frac{J}{g\cdot ^\circ C}
4 0
3 years ago
7) Sodium is much more apt to exist as a cation than chlorine because: a) chlorine is a gas and sodium is a solid b) chlorine ha
sleet_krkn [62]

Answer:

Option (d) chlorine has a greater ionization energy than sodium

Explanation:

Ionization energy is the energy required to remove an electron from a gaseous atom or ion. Sodium has just 1 electron in it's outmost shell and chlorine has 7.

Sodium needs 7 electrons to complete it's octet configuration and chlorine needs just 1.

Sodium can not attract 7 electrons to complete it's octet configuration instead it will easily lose the 1 electron in it's outmost shell to form cation. On the other hand, it will be difficult for chlorine to lose any of it's outmost electrons. This makes chlorine to have higher ionization energy than sodium.

6 0
3 years ago
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