Question

Pls help!!

Answer 1

Answer: D. 1600 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}$

$\text{Number of moles of nitrogen}==\frac{1000L}{22.4L}=44.6moles$

$\text{Number of moles of hydrogen}==\frac{2400L}{22.4L}=107.1moles$

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$  

According to stoichiometry :

3 moles of $H_2$ require 1 mole of $N_2$

Thus 107.1 moles of $H_2$ will require=$\frac{1}{3}\times 107.1=35.7moles$ of $N_2$

Thus $H_2$ is the limiting reagent as it limits the formation of product and $N_2$ is the excess reagent.

As 3 moles of $H_2$ give = 2 moles of $NH_3$

Thus 107.1 moles of $H_2$ give =$\frac{2}{3}\times 107.1=71.4moles$  of $NH_3$

Volume of $NH_3=moles\times {\text {Molar volume}}=71.4moles\times 22.4L/mol=1600L$

Thus volume of ammonia produced is 1600 L