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2 years ago

How is the distance formula related to the equation of a circle?

1 answer:

7 0

The distance formula is d = (x^2 + y^2)^(1/2) This is the same equation used for both. In other words, the equation of a circle gives the radius of the circle in terms of x and y, while the distance formula gives the distance from the origin to the final point in terms of x a

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HELP ME PLEASEEEEEEE

scoray [572]

Answer:

It would be in this order:

Types of Quads:

Rectangle

Square

Rhombus

Trapezoid

Type of Triangles:

Equaliteral

Isoceles

Scalene

Step-by-step explanation:

Hope it helps

6 0

2 years ago

Interior and Exterior Triangle Angles

k0ka [10]

Answer: 20.2
Add all the angles and set it equal to 180
Combine like terms
20x-2=180
X= 9.1

The equation for v is 2x+2
Replace x with 9.1 and then solve

3 0

2 years ago

Which three measurements could be the lengths of the sides of a triangle?

laila [671]

Answer:

i'm guessing b or a sorry if i'm wrong TwT

Step-by-step explanation:

sorry

3 0

2 years ago

Read 2 more answers

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

2 years ago

Evaluate the expression.<br> Drag the answer into the box to match the expression.

Lelu [443]

$27.((3^{3})^{-1} = 27.(27)^{-1} = 27 .\frac{1}{27} = 1$

This is because $3^{3} = 3 x 3 x 3 = 9 x 3 = 27$

And $(27)^{-1} means \frac{1}{27}$

For this reason, $27. (27)^{-1} = 1$

Positive indices mean we have to multiply the same number twice or thrice based on the value of the index. On the other hand, negative indices mean we have to divide by the same number twice or thrice based on the value of the index.

5 0

2 years ago

Read 2 more answers