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All you have to do to acquire the equation is to substitute the variables to the formula for A and simplify. Since A = 1/2*b*h and h = bsin(C), then A can be in terms of one variable only, which is b.
A = 1/2*b*bsin(c)
A = 1/2*b^2*sin(C)
Answer:
The interval from the sample of size 400 will be approximately <u>One -half as wide</u> as the interval from the sample of size 100
Step-by-step explanation:
From the question we are told the confidence level is 95% , hence the level of significance is
=> 
Generally from the normal distribution table the critical value of 
is
Generally the 95% confidence interval is dependent on the value of the margin of error at a constant sample mean or sample proportion
Generally the margin of error is mathematically represented as
Here assume that 
is constant so
=> 
=> 
So let 
and 
=> 
=> 
=> 
So From this we see that the confidence interval for a sample size of 400 will be half that with a sample size of 100
Answer:
Im dumb but cant you just be like, I subtracted 146° and 62°?
Answer:
Step-by-step explanation:
Let the speed of Masha = s, speed of Dasha = d
- Distance = 20 km
- Time difference = 20 min = 1/3 hr
- Speed difference = 2 km/h
<u>As per above info we get following equations:</u>
- s = d + 2
- 20/s + 1/3 = 20/d
<u>Substitute s and solve for d:</u>
<u>Get rid of fraction by multiplying all terms by 3d(d + 2):</u>
- 60d + d(d + 2) = 60(d + 2)
- 60d + d² + 2d = 60d + 120
- d² + 2d = 120
- d² + 2d + 1 = 121
- (d + 1)² = 11²
- d + 1 = 11
- d = 10
<u>Find s:</u>
<u>The answer is</u>
- Masha's speed 12 km/h and Dasha's speed 10 km/h
Answer:
8 and -2
Step-by-step explanation:
Let the numbers be l and s.
We have equations:
l = 5s + 18
3l + 4s = 16
Solve for s by substituting l into the second equation:
3(5s + 18) + 4s = 16
15s + 54 + 4s = 16
19s = 16 - 54
19s = -38
s = -38/19
s = -2
Find the value of l:
l = 5(-2) + 18
l = -10 + 18
l = 8
