So remember that the distance formula is
.
1.
![\sqrt{(4-4)^2+(-2-(-5))^2}\\ \sqrt{0^2+3^2}\\ \sqrt{0+9}\\ \sqrt{9}\\ 3](https://tex.z-dn.net/?f=%20%5Csqrt%7B%284-4%29%5E2%2B%28-2-%28-5%29%29%5E2%7D%5C%5C%20%5Csqrt%7B0%5E2%2B3%5E2%7D%5C%5C%20%5Csqrt%7B0%2B9%7D%5C%5C%20%5Csqrt%7B9%7D%5C%5C%203%20)
Distance between (4,-5) and (4,-2) is 3 units.
2.
![\sqrt{(1-(-1))^2+(1-4)^2}\\ \sqrt{2^2+(-3)^2}\\ \sqrt{4+9}\\ \sqrt{13}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%281-%28-1%29%29%5E2%2B%281-4%29%5E2%7D%5C%5C%20%5Csqrt%7B2%5E2%2B%28-3%29%5E2%7D%5C%5C%20%5Csqrt%7B4%2B9%7D%5C%5C%20%5Csqrt%7B13%7D%20)
Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.
Answer:
y = -5x + 20
Step-by-step explanation:
Lets start with the first given values for x and y
(2,10)
Lets try out the first equation
y = 5x + 4
y = 5(2) + 4
y = 14
This equation wouldn't work because the y value is not 10 when the x value is 2
y = 5x + 20
y = 5(2) + 20
y = 30
This equation doesn't work either
y = -5x + 20
y = -5(2) + 20
y = -10 + 20
y = 10
This would be the correct equation since your y value is 10 when the x value is 2
Answer:
1766.3
Step-by-step explanation:
V=4
/3πr^3
= 4/3(3.14)(7.5)^3
= 4/3(3.14)(421.88)
= 4/3(1324.69)
= 1766.25
= 1766.3
I hope this is right!
Volume of cylinder= /pi r square h
Taking /pi as 22/7
r= diameter/2
=5m
h=24m
V= 22/7*5 square*24
V=22*25*24/7
V=13200/7
V=1885.7 m cube
I would assume you would do base*width*weight to get your area.