Can someone give me the answer please
2 answers:
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The correct answer is: [B]: " 22 " .
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Explanation:
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Given:
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;
Solve when: "n = 3" ;
Rewrite the expression; substituting "3" for all values of "n" ; as follows:
→
;
The "6" cancels out to "2" ; & the "3" cancels out to "1" ;
→ {since: " {6 ÷ 3 = 2}" ; and since: " {2 ÷ 2 = 1}" .
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→ Since the "denominator" is "1" ; and any value, divided by "1"; results in that original value; we can eliminate the denominator.
→ Now, we can rewrite the expression as:
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→ " 2(3² + 2)" ;
= 2(9 + 2) ;
= 2(11) ;
= " 22 " .
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→ The answer is: " 22 " ; which is: Answer choice: [B]: " 22 " .
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_________________________________________________________
Explanation:
_________________________________________________________
Given:
_________________________________________________________
Solve when: "n = 3" ;
Rewrite the expression; substituting "3" for all values of "n" ; as follows:
→
The "6" cancels out to "2" ; & the "3" cancels out to "1" ;
→ {since: " {6 ÷ 3 = 2}" ; and since: " {2 ÷ 2 = 1}" .
_________________________________________________________
→ Since the "denominator" is "1" ; and any value, divided by "1"; results in that original value; we can eliminate the denominator.
→ Now, we can rewrite the expression as:
_________________________________________________________
→ " 2(3² + 2)" ;
= 2(9 + 2) ;
= 2(11) ;
= " 22 " .
_________________________________________________________
→ The answer is: " 22 " ; which is: Answer choice: [B]: " 22 " .
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Answers:
Vertical asymptote: x = 0
Horizontal asymptote: None
Slant asymptote: (1/3)x - 4
<u>Explanation:</u>
d(x) =
=
Discontinuities: (terms that cancel out from numerator and denominator):
Nothing cancels so there are NO discontinuities.
Vertical asymptote (denominator cannot equal zero):
3x ≠ 0
<u>÷3</u> <u>÷3 </u>
x ≠ 0
So asymptote is to be drawn at x = 0
Horizontal asymptote (evaluate degree of numerator and denominator):
degree of numerator (2) > degree of denominator (1)
so there is NO horizontal asymptote but slant (oblique) must be calculated.
Slant (Oblique) Asymptote (divide numerator by denominator):
- <u>(1/3)x - 4 </u>
- 3x) x² - 12x + 20
- <u>x² </u>
- -12x
- <u>-12x </u>
- 20 (stop! because there is no "x")
So, slant asymptote is to be drawn at (1/3)x - 4