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3 years ago

Is my answer correct or incorrect? Explain please. Thank you

Mathematics

2 answers:

Ber [7]3 years ago

8 0

3 sandwich choices
2 side item choices
4 beverage choices

Let's say the sandwich choices were PB&J, Ham, and Turkey
Let's say the sides were fries and mandarin oranges
Let's say the beverages were water, orange juice, milk, soda

PB&J
Ham
Turkey

Fries
Mandarin Oranges

Water
OJ
Milk
Soda

The combinations can be as follows:

PB&J, Fries, Water
PB&J, Fries, OJ
PB&J, Fries, Milk
PB&J, Fries, Soda
PB&J, Mandarin Oranges, Water
PB&J, Mandarin Oranges, OJ
PB&J, Mandarin Oranges, Milk
PB&J, Mandarin Oranges, Soda
Ham, Fries, Water
Ham, Fries, OJ
Ham, Fries, Milk
Ham, Fries, Soda
Ham, Mandarin Oranges, Water
Ham, Mandarin Oranges, OJ
Ham, Mandarin Oranges, Milk
Ham, Mandarin Oranges, Soda
Turkey, Fries, Water
Turkey, Fries, OJ
Turkey, Fries, Milk
Turkey, Fries, Soda
Turkey, Mandarin Oranges, Water
Turkey, Mandarin Oranges, OJ
Turkey, Mandarin Oranges, Milk
Turkey, Mandarin Oranges, Soda

So your answer is correct: There's 24 lunch combinations that can be made.

Hope that helps!

True [87]3 years ago

4 0

Yes because 3 * 2 * 4 = 24

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2 years ago

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3 years ago

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|h-3|<5 how do I solve using inequalities

Readme [11.4K]

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8 0

2 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

2 years ago

The gender of people attending a football game. a. Qualitative/nominal b.qualitative/ordinal c. Quantitative/continuous d. Quant

shtirl [24]

Answer: <span>Qualitative/nominal

Gender is expressed as qualitative and nominal. Qualitative because it doesn't have a number, so it's not quantitative. It also nominal because gender is considered as having the same level. Another example of nominal is blood group or religion.
If it has an order of level(example: severity mild to severe), it will be ordinal.</span>

3 0

3 years ago