3 sandwich choices 2 side item choices 4 beverage choices
Let's say the sandwich choices were PB&J, Ham, and Turkey Let's say the sides were fries and mandarin oranges Let's say the beverages were water, orange juice, milk, soda
PB&J Ham Turkey
Fries Mandarin Oranges
Water OJ Milk Soda
The combinations can be as follows:
PB&J, Fries, Water PB&J, Fries, OJ PB&J, Fries, Milk PB&J, Fries, Soda PB&J, Mandarin Oranges, Water PB&J, Mandarin Oranges, OJ PB&J, Mandarin Oranges, Milk PB&J, Mandarin Oranges, Soda Ham, Fries, Water Ham, Fries, OJ Ham, Fries, Milk Ham, Fries, Soda Ham, Mandarin Oranges, Water Ham, Mandarin Oranges, OJ Ham, Mandarin Oranges, Milk Ham, Mandarin Oranges, Soda Turkey, Fries, Water Turkey, Fries, OJ Turkey, Fries, Milk Turkey, Fries, Soda Turkey, Mandarin Oranges, Water Turkey, Mandarin Oranges, OJ Turkey, Mandarin Oranges, Milk Turkey, Mandarin Oranges, Soda
So your answer is correct: There's 24 lunch combinations that can be made.
The options aren't given, however, the range of amount spent could be calculated
Answer:
Kindly check explanation
Step-by-step explanation:
Paula purchase 3 dvd and 7 cds and spent between 90 and 100. Each dvd costs the same amount the price of cd is 10 select all amounts that could be the price of the dvd
Given that :
DVD costs the same amount
Number of DVD's = 3
Cost of cds = 10
Number of cds = 7
Total cost of cd's = 10 * 7 = 70
Let the price of DVD = x
Total amount spent = 90 - 100
Lowest price of DVD :
(amount spent - price of cd) / number of dvd
(90 - 70) / 3 = 20 /3 = 6.667
Highest price :
(100 - 70) / 3 = 30 / 3 = 10
Hence the pice of each DVD will range between /
6.6666 and 10.
Hence, prices listed within the range above are possible.
