3 sandwich choices 2 side item choices 4 beverage choices
Let's say the sandwich choices were PB&J, Ham, and Turkey Let's say the sides were fries and mandarin oranges Let's say the beverages were water, orange juice, milk, soda
PB&J Ham Turkey
Fries Mandarin Oranges
Water OJ Milk Soda
The combinations can be as follows:
PB&J, Fries, Water PB&J, Fries, OJ PB&J, Fries, Milk PB&J, Fries, Soda PB&J, Mandarin Oranges, Water PB&J, Mandarin Oranges, OJ PB&J, Mandarin Oranges, Milk PB&J, Mandarin Oranges, Soda Ham, Fries, Water Ham, Fries, OJ Ham, Fries, Milk Ham, Fries, Soda Ham, Mandarin Oranges, Water Ham, Mandarin Oranges, OJ Ham, Mandarin Oranges, Milk Ham, Mandarin Oranges, Soda Turkey, Fries, Water Turkey, Fries, OJ Turkey, Fries, Milk Turkey, Fries, Soda Turkey, Mandarin Oranges, Water Turkey, Mandarin Oranges, OJ Turkey, Mandarin Oranges, Milk Turkey, Mandarin Oranges, Soda
So your answer is correct: There's 24 lunch combinations that can be made.
Let be the true mean match score. The null hypothesis is and the alternative hypothesis is (upper-tail alternative). When the test shows that the mean match score is more than 80 when actually is equal to 80 a Type I error is made. On the other hand, when the test shows that the mean match score is equal to 80 when actually is more than 80 a type II error is made. Therefore, when the test shows that the mean match score is more than 80 when the person does not actually have a fingerprint match, does not correspond to a Type I error neither to a Type II error.
T= 21.79x + 3.99x + 6.89x where t is the total cost and x is the number of brushes/rollers/paint cans you buy. You don't need a different variable for each item because you buy the same amount of each.
Given: <span>2x-y-3=0. find </span>equation for the line perpendicular to the given line that goes through the given point:<span> (2;-1)koord of direction vector (i`m not know how it is called at you, because i'm from russia)</span><span> => (x-0)/2=(y-4)/-1 (</span>canonical <span>equation) =>x+2y-8=0(general </span><span>equation) </span> <span>further: {x+2y-8=0 {2x-y-3 =0 => y=13/5 x=14/5
(14/5; 13/5) - koord point on line </span>|dist|=sqrt( (14/5-0)^2 + (13/5-4)^2 ) = sqtr(7.72) = 2.78
