3 sandwich choices 2 side item choices 4 beverage choices
Let's say the sandwich choices were PB&J, Ham, and Turkey Let's say the sides were fries and mandarin oranges Let's say the beverages were water, orange juice, milk, soda
PB&J Ham Turkey
Fries Mandarin Oranges
Water OJ Milk Soda
The combinations can be as follows:
PB&J, Fries, Water PB&J, Fries, OJ PB&J, Fries, Milk PB&J, Fries, Soda PB&J, Mandarin Oranges, Water PB&J, Mandarin Oranges, OJ PB&J, Mandarin Oranges, Milk PB&J, Mandarin Oranges, Soda Ham, Fries, Water Ham, Fries, OJ Ham, Fries, Milk Ham, Fries, Soda Ham, Mandarin Oranges, Water Ham, Mandarin Oranges, OJ Ham, Mandarin Oranges, Milk Ham, Mandarin Oranges, Soda Turkey, Fries, Water Turkey, Fries, OJ Turkey, Fries, Milk Turkey, Fries, Soda Turkey, Mandarin Oranges, Water Turkey, Mandarin Oranges, OJ Turkey, Mandarin Oranges, Milk Turkey, Mandarin Oranges, Soda
So your answer is correct: There's 24 lunch combinations that can be made.
Note the definition of a rectangle. All angles must be 90°, and opposite sides are parallel and congruent.
It says that Andre "drew a quadrilateral with <em>four right angles and two pairs of congruent sides</em>.", making rectangle a candidate as an answer.
A circumscribed angle is that which is formed by the intersection of the two tangent lines in a circle. With this, we can conclude that segments AC and AB are tangent to circle O. The tangent lines forms a right angle with the radius of the circle drawn from the center of the circle to the tangent point.
By the explanation above, we can say that angles C and B are equal to 90° and that triangle ACO and triangle ABO are congruent. Which means that segment AC is equal to segment AB. Thus, the length of AB is also 4.
