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Molodets [167]
3 years ago
5

The graph below shows the amount of money Janet earned at her new job.

Mathematics
2 answers:
lara [203]3 years ago
4 0

Answer:

b

Step-by-step explanation:

lina2011 [118]3 years ago
3 0

Answer:

15

Step-by-step explanation:

Janet earns 15 dollars.

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A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe
enyata [817]

Step-by-step explanation:

Find P(X=4)

By doing 4C4* (0.15)^4*(0.85)^0

Find P(X=1, 2,3) by doing 1- Ans you get for P(X=4)

4 0
3 years ago
Answer the following question about the function whose derivative is given below
Komok [63]

Answer:

a) The critical points are x = 3 and x = -6.

b) f is decreasing in the interval (-\infty, -6)

f is increasing in the intervals (-6,3) and (3,\infty).

c) Local minima: x = -6

Local maxima: No local maxima

Step-by-step explanation:

(a) what are the critical points of f?

The critical points of f are those in which f^{\prime}(x) = 0. So

f^{\prime}(x) = 0

(x-3)^{2}(x+6) = 0

So, the critical points are x = 3 and x = -6.

(b) on what intervals is f increasing or decreasing? (if there is no interval put no interval)

For any interval, if f^{\prime} is positive, f is increasing in the interval. If it is negative, f is decreasing in the interval.

Our critical points are x = 3 and x = -6. So we have those following intervals:

(-\infty, -6), (-6,3), (3, \infty)

We select a point x in each interval, and calculate f^{\prime}(x).

So

-------------------------

(-\infty, -6)

f^{\prime}(-7) = (-7-3)^{2}(-7+6) = (100)(-1) = -100

f is decreasing in the interval (-\infty, -6)

---------------------------

(-6,3)

f^{\prime}(2) = (2-3)^{2}(2+6) = (1)(8) = 8

f is increasing in the interval (-6,3).

------------------------------

(3, \infty)

f^{\prime}(4) = (4-3)^{2}(4+6) = (1)(10) = 10

f is increasing in the interval (3,\infty).

(c) At what points, if any, does f assume local maximum and minima values. ( if there is no local maxima put mo local maxima) if there is no local minima put no local minima

At a critical point x, if the function goes from decreasing to increasing, it is a local minima. And if the function goes from increasing to decreasing, it is a local maxima.

So, for each critical point is this problem:

At x = -6, f goes from decreasing to increasing.

So x = -6, f assume a local minima value

At x = 3, f goes from increasing to increasing. So, there it is not a local maxima nor a local minima. So, there is no local maxima for this function.

4 0
3 years ago
How do I solve this 6-3=□-2
Sonja [21]
Well, first what is 6-3=3 so now whats 3-2? 3-2=1 
6-3=3-2
8 0
3 years ago
Helppp me faststttttt plzzzzz
Sophie [7]

Answer:

Step-by-step explanation:

x + 25 + 4x + 10 = 180

5x + 35 = 180

5x = 145

x = 29

<1 = 29 + 25 = 54

<2= 4(29) + 10 = 116 + 10 = 126

7 0
3 years ago
1.06 SINUSOIDAL GRAPHS VERTICAL SHIFT
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Answer:

I do not understand very well but they are already helping me

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