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Molodets [167]
3 years ago
5

The graph below shows the amount of money Janet earned at her new job.

Mathematics
2 answers:
lara [203]3 years ago
4 0

Answer:

b

Step-by-step explanation:

lina2011 [118]3 years ago
3 0

Answer:

15

Step-by-step explanation:

Janet earns 15 dollars.

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35 points please help me i will make you the brainliest
forsale [732]
Hey You!

The images are blurry and I cannot make out most of the questions. I'll solve as many as I can see!

27. ANSWER:

Students A and D have a combined score of 0 because 4 + -4 = 0
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28. SOLUTION/ANSWER:

STEP 1: 12.40 - 0.72 = 11.68

STEP 2: 11.68/2 = 5.84

Answer: Each souvenir cost $5.84.
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29. SOLUTION/ANSWER:

(-68) - 214 = -282

Answer: The lowest elevation in California is -282 feet.

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33. SOLUTION/ANSWER:

60/3 = 20

Answer: The diver's change in depth was -20 per min.

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34. SOLUTION/ANSWER:

-43 - (-34) = -9. The difference between the two is -9.

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35. SOLUTION/ANSWER:

-64.4 + (3.22) = -67.62

Answer: Equals -67.62

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37. SOLUTION/ANSWER:

3.375 = 3 3/8 as a mixed number and 27/8 as an improper fraction.

Answer: 3 3/8 (or 27/8).

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38. SOLUTION/ANSWER:

3 ÷ 5 = 0.6

5 + 0.6 = 5.6

Answer: 5 3/5 = 5.6

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39. SOLUTION/ANSWER:

1.5 + 2.8 = 4.3

Haley jogged 4.3 km that day.

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I cannot see the other questions. If you can perhaps message them to me I can try to help you! :)
8 0
3 years ago
12. Name the property the equation illustrates.
Vesnalui [34]

the answer is A. the commutative property of addition. this property states that no matter what order you put the numbers, the outcome will be the same.

Hope this helps!

4 0
3 years ago
Select all tables thaf represent A proportional relationship between x and y.
Whitepunk [10]
A is the answer babygirl.
4 0
3 years ago
To run a mile, Jamal must run 4 laps around the track. His goal is to run 3 miles. Jamal has run 9 laps so far.
vodka [1.7K]
Don’t really know what your question is but 4 laps times 3 miles is 12 laps. He’s got 3 more laps to finish his goal.

Pro tip: Include the actual question
7 0
3 years ago
Read 2 more answers
Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$
Anna [14]

Answer:

\large\boxed{1\dfrac{1}{3}\ u^2}

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}

6 0
3 years ago
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