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leonid [27]
4 years ago
15

A sealed, carbonated soda has a partial pressure of co2 of 4.0 atm at 25 degrees celsius. the concentration of co2 in the soda i

s 0.14M. find the concentration of CO2 in the soda after the bottle is opened, and equilibrates at a partial pressure of 3.0 X 10^-4 atm. The henry's law constant is 3.4 X 10^-2 mol/L atm.
Chemistry
1 answer:
MArishka [77]4 years ago
8 0

Answer:

1.0 × 10⁻⁵ mol/L

Explanation:

The concentration of a gas (C) in a liquid depends on its partial pressure (P), as expressed in Henry's law.

C = k × P

where,

k is the henry's law constant

When the partial pressure of the gas equilibrates at 3.0 × 10⁻⁴ atm, its concentration in the liquid is:

C = k × P

C = 3.4 × 10⁻² mol/L.atm × 3.0 × 10⁻⁴ atm

C = 1.0 × 10⁻⁵ mol/L

You might be interested in
Which of the following is most likely to dissolve in NH3? A) CO2 B) CH4 C) H2S D) BH3
dem82 [27]

Answer:

C) H2S

Explanation:

In chemistry, the dissolution of one substance in another is dependent on the magnitude of intermolecular interaction between the two substances.  Hence, if two substances do not interact in one way or the other, then one can not dissolve the other.

Let us consider the fact that NH3 is a polar molecule and it is a general principle that like dissolves like. Hence, only H2S which is also a polar molecule can effectively interact with  NH3 due to dipole-dipole interaction between the two molecules.

Also, ammonia reacts with hydrogen sulphide as follows;

2NH3 + H2S → (NH4)2S

Hence H2S is more likely to dissolve in NH3.

5 0
3 years ago
What mass of Sodium Chloride is required to make 100.0 mL of 3.0 M solution?
Julli [10]

Answer:

17.55 g of NaCl

Explanation:

The following data were obtained from the question:

Molarity = 3 M

Volume = 100.0 mL

Mass of NaCl =..?

Next, we shall convert 100.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100/1000

100 mL = 0.1 L

Therefore, 100 mL is equivalent to 0.1 L.

Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:

Molarity = 3 M

Volume = 0.1 L

Mole of NaCl =?

Molarity = mole /Volume

3 = mole of NaCl /0.1

Cross multiply

Mole of NaCl = 3 × 0.1

Mole of NaCl = 0.3 mole

Finally, we determine the mass of NaCl required to prepare the solution as follow:

Mole of NaCl = 0.3 mole

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.3 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.3 × 58.5

Mass of NaCl = 17.55 g

Therefore, 17.55 g of NaCl is needed to prepare the solution.

5 0
3 years ago
Which one of the following questions about animals called affairs, pictured above, is the scientific question?
tino4ka555 [31]

The answer is B...

because any of the others could have an opinion based answer but B will always be the same its a fact not opinion.

3 0
4 years ago
A. 20 moles of NH3 are needed to produce how many moles of H2O?
tiny-mole [99]

a. 30 moles of H₂O

b. 2.33 moles of N₂

<h3>Further explanation</h3>

Given

a. 20 moles of NH₃

b. 3.5 moles of O₂

Required

a. moles of H₂O

b. moles of N₂

Solution

Reaction

4NH₃+3O₂⇒2N₂+6H₂O

a. From the equation, mol ratio NH₃ : H₂O = 4 : 6, so mol H₂O :

=6/4 x mol NH₃

= 6/4 x 20 moles

= 30 moles

b. From the equation, mol ratio N₂ : O₂ = 2 : 3, so mol N₂ :

=2/3 x mol O₂

= 2/3 x 3.5 moles

= 2.33 moles

7 0
3 years ago
What is the empirical formula of a compound containing 5.03 grams carbon, 0.42 grams hydrogen, and 44.5 grams chlorine?
djverab [1.8K]

The empirical formula of the compound is CHCl₃.

<h3>Calculation:</h3>

Given,

Mass of carbon = 5.03 g

Mass of hydrogen = 0.42 g

Mass of chlorine = 44.5 g

Molecular weight of carbon = 12 g

Molecular weight of hydrogen = 1 g

Molecular weight of chlorine = 35.4 g

First, calculate the moles of each element,

                      Moles = given mass/ molecular weight

Moles of carbon = 5.03/12 = 0.42

Moles of hydrogen = 0.42/1 = 0.42

Moles of chlorine = 44.5/ 35.4 = 1.26

Divide the moles of each element by the smallest number of moles,

0.42 mol of C/ 0.42 = 1 C

0.42 mol of H/ 0.42 = 1 H

1.26 mol of Cl/0.42 = 3 Cl

The ratio of elements is 1:1:3

Therefore the empirical formula of the compound will be CHCl₃.

Learn more about empirical formula here:

brainly.com/question/20708102

#SPJ4

5 0
2 years ago
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