What is the solution to this system of linear equations? 12q+3r=15 -4q-4r=-44
1 answer:
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Answer:
Step-by-step explanation:
Comparing the triangles in the given questions, the following can be deduced:
5. The scale factor = =
≠
So that;
QR is similar to UT, PR is similar to US, but PQ is NOT similar to TS.
Thus, the triangles are NOT similar.
6. Scale factor = =
=
= 1.5
So that;
QR is similar to UT, PR is similar to US, but PQ is similar to TS.
Thus, the triangles are similar by Side-Side-Side (SSS).
7. Here, an exact scale factor can not be determined. Thus, the triangles are NOT similar.
The distance between two points can be calculated using the following formula:
distance = sqrt [ (x2-x1)^2 + (y2-y1)^2]
Now, we are given the two points (5,4) and (1,-2)
Substitute with the given points in the above equation to get the distance as follows:
distance = sqrt [(1-5)^2 + (-2-4)^2]
distance = sqrt [16+36] = sqrt[52]
distance = 2√13 = 7.2111 units
distance = sqrt [ (x2-x1)^2 + (y2-y1)^2]
Now, we are given the two points (5,4) and (1,-2)
Substitute with the given points in the above equation to get the distance as follows:
distance = sqrt [(1-5)^2 + (-2-4)^2]
distance = sqrt [16+36] = sqrt[52]
distance = 2√13 = 7.2111 units