3 years ago

What is the solution to this system of linear equations? 12q+3r=15 -4q-4r=-44

1 answer:

5 0

12q+3r=15
-4q-4r=-44
-4q=-44+4r
q=11-r
12(11-r)+3r=15
132-12r+3r=15
132-9r=15
117=9r
r=13
-4q-4(13)=-44
-4q-52=-44
-4q=8
q=-2

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