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shepuryov [24]
3 years ago
12

Is the function y=0.5x linear?

Mathematics
2 answers:
Dmitry [639]3 years ago
4 0
Yes.

A linear equation is an equation of a straight line, which means that the degree of a linear equation must be
0
0
or
1
1
for each of its variables. In this case, the degree of variable
y
y
is
1
1
and the degree of variable
x
x
is
1
1
.
exis [7]3 years ago
4 0

Answer:

Yes, it is linear.

Step-by-step explanation:

There is a constant change in the slope. Basically, if it is in y=mx+b form then it is linear. But if the slope is squared then it is not linear.

(I'll take that brainliest now)

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((Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!
Lina20 [59]

Answer:

A


Step-by-step explanation:

A series is said to be convergent if |r| < 1. Where r is the common ratio of the series.

If |r| ≥ 1 then the geometric series diverges.

12/5 + 48/25 + 192/125 + ....

r = 192/125 ÷ 48/25 = 4/5

r = 48/25 ÷ 12/5 = 4/5

In the series, r is less than 1. So the series is convergent.

5 0
3 years ago
How would you solve 4667 divided by 7
lidiya [134]

Answer:

666.7 with long division

Step-by-step explanation:

4667 can be divided by 7 by doing long division. I tried to show this best I could.

__666.7______

7|4667.0

-42

46

-42

47

-42

50

-49

0

and so on

7 0
3 years ago
Find the product. 2 4/10 =
AleksAgata [21]

Answer: 2 2/5 is answer decimal answer is 2.4

Step-by-step explanation:

hope this helpss!!

3 0
3 years ago
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Soloha48 [4]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
100 POINTS!! OMG YOU NEED TO SOLVE THIS!
natita [175]

Answer:

The correct answer is: \Delta BDE \cong \Delta BFK by <em>rule</em> ASA rule of congruence.

Step-by-step explanation:

First let us prove \Delta BDE \cong \Delta BFK by rule ASA (rule of congruence).

<u>Congruent side:</u>

\overline{BD} \cong \overline{BF} (Given)

<u>Congruent angles:</u>

1. By definition of perpendicular,

\angle{BFK} = 90 \textdegree \ (Since \ \overline{FK} \ is \ perpendicular \ to \ \overline{AB} \ (\overline{FK} \perp \overline{AB} =Given))

Also,

\angle{BDE} = 90 \textdegree \ (Given)

Therefore,

\angle{BDE} \cong \angle{BFK}

or you can say,

\angle{D} \cong \angle{F}

2. Common angle between \Delta BDE \ and \ \Delta BFK is \angle{B}

In a nutshell, in \Delta BDE,

\angle{B} (Angle)

\overline{BD} (Side)

\angle{BDE} (Angle)

are congruent to the following angle, side and angle of \Delta BFK:

\angle{B} (Angle)

\overline{BF} (Side)

\angle{BFK} (Angle)

Therefore, by ASA rule of congruence, we can say \Delta BDE \cong \Delta BFK.

<em>Since both triangles are congruent</em>, the sides \overline{ED} and \overline{FK} are also congruent.

5 0
3 years ago
Read 2 more answers
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