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Snowcat [4.5K]
3 years ago
15

What is the coefficient in the expression shown? 42 + 2c 2 42 c 2c

Mathematics
2 answers:
Tpy6a [65]3 years ago
8 0

That could use some punctuation.

I think the expression is

42 + 2c

We call 42 and 2c the terms, 42 is the constant or the constant term, 2c is the linear term, with a coefficient of 2 and variable c.

Answer: 2


Leokris [45]3 years ago
5 0

Answer: A. 2

Step-by-step explanation:

That could use some punctuation.

I think the expression is

42 + 2c

We call 42 and 2c the terms, 42 is the constant or the constant term, 2c is the linear term, with a coefficient of 2 and variable c.

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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822772

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}


Make the following substitution:

\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}


and then, the integral (i) becomes

=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}


Integrate it by applying the power rule:

\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}


Now, substitute back for u = sin x, so the result is given in terms of x:

\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}


\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

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