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ss7ja [257]
2 years ago
10

What are some differences between linear equations and inequalities, specifically their solutions and the process of finding tho

se solutions?
Mathematics
1 answer:
Scorpion4ik [409]2 years ago
6 0

Answer:

difference between linear equations and inequalities is the solution set. A linear equation of two variables can have more than one solution. For instance, with x = 2_y_ + 3, (5, 1), then (3, 0) and (1, -1)

Step-by-step explanation:

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Lynna [10]

Answer:

23

Step-by-step explanation:

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5 0
3 years ago
Evaluate5− t/3 when t=12 ​
Novosadov [1.4K]

Answer:

1

Step-by-step explanation:

5 -  \frac{t}{3} =  \frac{5}{1} - \frac{12}{3} = 5 - 4 = 1

or

5 -  \frac{t}{3} =  \frac{5}{1} -  \frac{12}{3} =  \frac{15 - 12}{3} =  \frac{3}{3} = 1

Hope this helps ;) ❤❤❤

8 0
2 years ago
Read 2 more answers
A DVD costs $17.45. What is 6.75% sales tax?
luda_lava [24]

6.75 % x 17.45

= $18.63

6 0
3 years ago
Read 2 more answers
The amount of time it takes to see a doctor a CPT-Memorial is normally distributed with a mean of 33 minutes and a standard devi
Eva8 [605]

Answer:

a) <em>Z-score = 0.75</em>

b) <em>Z-score = -32.833</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that mean of the Population = 33

Given a standard deviation of the Population = 12

Let 'X' be a random variable in a normal distribution

Let 'X' = 42

<u><em>Step(ii):-</em></u>

<em>      </em>Z = \frac{x-mean}{S.D}<em></em>

<em>     </em>Z = \frac{42-33}{12} = 0.75<em></em>

<u><em>Step(iii):-</em></u>

<em>Given that mean of the Population = 89</em>

Given a standard deviation of the Population = 1

Let 'X' be a random variable in a normal distribution

Let 'X⁻ = 82

<em>   </em>Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }<em></em>

<em>     </em>Z = \frac{82-89}{\frac{1}{\sqrt{22} } } =  -32.833<em></em>

<em>Z-score = -32.833</em>

<em></em>

7 0
3 years ago
Amuseumcharges forgeneraladmission and exhibitions. Admission and 3 exhibitionscosts $45. Admission and 5 exhibitionscosts $65.
leonid [27]

Answer:

The price of the admission is 15.

Step-by-step explanation:

From the information given, you can write the following equations:

a+3e=45 (1)

a+5e=65 (2), where:

a is the admission cost

e is the exhibition cost

First, you can solve for a in (1):

a=45-3e (3)

Second, you can replace (3) in (2):

45-3e+5e=65

45+2e=65

2e=65-45

2e=20

e=20/2

e=10

Finally, you can replace the value of e in (3):

a=45-3e

a=45-3(10)

a=45-30

a=15

According to this, the price of the admission is 15.

3 0
3 years ago
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