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valina [46]
3 years ago
12

If you can save it and solve it there on the paper

Mathematics
1 answer:
frez [133]3 years ago
4 0

Answer:

2a). Y= 1. 3= x

2b). Y=4 x= 1

3).

Y= x²+3x-18

For -5

First difference

10

Second difference

-8

For -4

First difference

4

Second difference

-14

For -3

First difference

9-9= 0

Second difference

-18

For -2

First difference

-2

Second difference

-20

For -1

First difference

-2

Second difference

-20

For 0

First difference

0

Second difference

-18

The relation ia a quadratic relation because of the highest Power of x to be 2

Step-by-step explanation:

For

Y=- x+4. Y= 1

Y=x-2. 1= x-2

2y =2. 1+2= x

Y= 1. 3= x

For

Y= x+3. 1= x

Y= 3x+1. Y= 3+1

0= 2x-2. Y= 4

2= 2x

1= x

Y= x²+3x-18

For -5

First difference

25-15= 10

Second difference

10-18= -8

For -4

First difference

16-12= 4

Second difference

4-18= -14

For -3

First difference

9-9= 0

Second difference

0-18 = -18

For -2

First difference

4-6= -2

Second difference

-2-18= -20

For -1

First difference

1-3 = -2

Second difference

-2-18 = -20

For 0

First difference

0+0 = 0

Second difference

0 -18= -18

The relation ia a quadratic relation because of the highest Power of x to be 2

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The value of x is 1.14 or x = -1.47

We find the value of x in the quadratic equation 3x^2 +x-5=0

Using the formula: (-b ± √ (b²- 4 a c)) / (2a)

Where the value of a = 3, b = 1 and c = -5

Substituting the above values (a = 3, b = 1 and c = -5)

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