we are given
![f(x)=x^3-64](https://tex.z-dn.net/?f=%20f%28x%29%3Dx%5E3-64%20)
Since, we have to find zeros
so, we can set f(x)=0
and then we can solve for x
![f(x)=x^3-64=0](https://tex.z-dn.net/?f=%20f%28x%29%3Dx%5E3-64%3D0%20)
![x^3-64=0](https://tex.z-dn.net/?f=%20x%5E3-64%3D0%20)
We will add both sides 64
![x^3-64+64=0+64](https://tex.z-dn.net/?f=%20x%5E3-64%2B64%3D0%2B64%20)
![x^3=64](https://tex.z-dn.net/?f=%20x%5E3%3D64%20)
Take cube root both sides
![\sqrt[3]{x^3} =\sqrt[3]{64}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%5Csqrt%5B3%5D%7B64%7D%20%20)
...........Answer
Answer:
The wingspan of a pelican is 1 8/15 feet longer than the wingspan of an eagle.
(1 whole 8/15 feet)
Step-by-step explanation:
We'll need to find a common denominator for the fractions. 15 is the lowest number divisible by both 5 and 3, so we'll use 15. For this problem, it's also easier to convert to improper fractions, in my opinion.
Pelican:
8 1/5 = 41/5
41/5 x 3/3 = 123/15
Eagle:
6 2/3 = 20/3
(20/3) x (5/5) = 100/15
Find the difference:
123/15 - 100/15 = 23/15 = 1 8/15
Please let me know if you have questions.
Answer:
Perimeter
Step-by-step explanation:
Perimeter is the distance all round a particular shape. Since we are not given the shape of her bedroom, we may not have a particular formula that was uses to find the perimeter. Despite all that, the only way that she could arrive to conclusion that 36 meters of light are needed, then Supriya it is by finding the perimeter.
Answer:
0.29287
Step-by-step explanation:
You want to use the binomial cumulative distribution function (binomcdf). The purpose of this function is that it allows you to obtain the probability of observing less than or equal to x successes in n trials, with the probability p of success on a single trial.
x in this case is 182, n is 200, and p is 0.9005. Essentially by inputting these values, we find the probability that out of 200 passengers with a 0.9005 chance of getting on the plane, that 182 or less show up.
This gives us P(x <= 182) = 0.70713. (You need your calculator for this step, input the values above in the binomcdf function)
We want to find the probability of more than 182 passengers showing up though, so it would be 1 - 0.70713 = 0.29287.
Thus the probability that when 200 reservations are accepted for the flight, there are more passengers than seats available is 0.29287.
you flip the ones on the bottom and put them on top