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Helga [31]
3 years ago
12

Y=|x−3|+|x+2|−|x−5|, if 3

Mathematics
1 answer:
denis-greek [22]3 years ago
5 0

Answer:

Step-by-step explanation:

I take it you want x = 3

y = abs(3 - 3) + abs(3 + 2) - abs(3 - 5)

y = 0 + 5 - abs(-2)

y = 0 + 5 - (2)

y = 0 + 5 - 2

y = 3

If you meant something else please leave a note.

Now all you do is redo the problem for 5

y = abs(5 - 3) + abs(5 + 2) - abs(5 - 5)

y = abs(2) + abs(7) - abs(0)

y = 2 + 7 - 0

y = 9

Now set up your inequality

3 < y < 9

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An angle, θ, is in standard position. The terminal side of the angle passes through the point (4, 5).
lara31 [8.8K]

Answer:

cos Θ = \frac{4}{\sqrt{41} }

Step-by-step explanation:

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