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tensa zangetsu [6.8K]
3 years ago
7

A certain library assesses fines for overdue books as follows. on the first day that a book is overdue, the total fine is $0.10.

for each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. book on the fourth day it is overdue?
Mathematics
1 answer:
Volgvan3 years ago
3 0
It the fourt day the total is 0.70 because
Day one: .10
Day two: you double it so .20
Day three: you double it again so .40
Day four: you add .30 so .70 is the total
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What is a formula for the nth term of the given sequence? 50, -20,8...​
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Answer:

L = 50 * (-0.4)^(n - 1)

Step-by-step explanation:

r = t2/t1 = -20/50 = - 0.4

a = 50

L = 50 * (r)^(n - 1)      Let's  see if we can get the answer when n = 3

L=50 * (-0.4)^(3 -1)

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Andrea's Sequoia gets 12 miles per gallon while driving in the city, and 20 miles per gallon while on the highway. The last time
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60miles

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x + y = 280

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A survey conducted by a leading HMO found that of 2000 women, 340 were heavy smokers and 25 had emphysema. Of those who had emph
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Answer:

The events being a heavy smoker and having emphysema are not independent.

Step-by-step explanation:

We are given the following in the question:

Number of women = 2000

Number of heavy smoker = 340

Number of women who has emphysema = 25

Number of women who has emphysema and are heavy smoker = 21

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

P(Smoker) =

P(S) = \dfrac{340}{2000}=0.17

P(emphysema) =

P(E) = \dfrac{25}{2000}= 0.0125

P(Smoker and emphysema) =

P(S\cap E) = \dfrac{21}{2000} = 0.0105

Two events A and B are said to be independent if

P(A\cap B)=P(A)\times P(B)

Checking conditions for independence:

P(S)\times P(E) = 0.17\times 0.0125=0.002125\\P(S)\times P(E) \neq 0.0105\\P(S)\times P(E)\neq P(S\cap E)

Thus, the events being a heavy smoker and having emphysema are not independent.

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