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IrinaVladis [17]
3 years ago
7

Helpppppppppppp?????

Mathematics
1 answer:
kirill115 [55]3 years ago
7 0

Answer:

14

Step-by-step explanation:

Since both blue chords are perpendicular to the equally long bisectors from the center of the circle, they must have the same length. Since the length of the bottom blue chord is 7*2=14, x must also be 14. Hope this helps!

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Find the difference(i accidentally pressed on the wrong answer)
MariettaO [177]

Answer:

=  > 8 \frac{1}{4}  - 3 \frac{5}{6}

=  >  \frac{33}{4}  -  \frac{23}{6}

=  >  \frac{33 \times 3}{4 \times 3}  -  \frac{23 \times 2}{6 \times 2}

=  >  \frac{99}{12}  -  \frac{46}{12}

=  >  \frac{99 - 46}{12}

=  >  \frac{53}{12}

=  > 4 \frac{5}{12}

8 0
2 years ago
Satara was having fun playing poker. She needed the next two cards dealt to be hearts so she could make a flush (five cards of t
evablogger [386]

Answer:

7%

Step-by-step explanation:

Given the following :

Total Number of cards left in deck = 10

Number of hearts left in deck = 3

Probability = (required outcome / Total possible outcomes)

Required outcome = hearts card in deck

Two cards are to be dealt to Satara without replacement :

Probability of 1st card being hearts :

P(1st card being hearts) = required outcome / Total possible outcomes

P(1st card being hearts) = 3 / 10

Probability of 2nd card being hearts :

Since it is without replacement :

Required outcome = (3 - 1). = 2

Total possible outcomes = (10 - 1) = 9

P(2nd card being hearts) = 2 /9

Probability of the two cards being hearts :

(3 / 10 × 2/9) = 6 /90 = 0.0666

0.06666 × 100% = 6.66%

= 7% (nearest whole number)

3 0
2 years ago
What should be added to a²-2ab+b² to get a²-ab-2b² ​
dybincka [34]

<u>SOLUTION</u><u>:</u>

<u>what should be added to a²-2ab+b² to get a²-ab-2b² </u>

let the added no is P

  • \pmb{P+(a^2-2ab+b^2)=(a^2-ab-2b^2) }

  • \pmb{P=(a^2-ab-2b^2)-(a^2-2ab+b^2) }

  • \pmb{P=a^2-ab-2b^2-a^2+2ab-b^2 }

  • \pmb{P=ab-3b^2 }

\therefore{\pmb{ab-3b^2 }} should be added to a²-2ab+b² to get a²-ab-2b²

5 0
2 years ago
Simplify 3³ × 3²
Natali [406]
3 to the 5th power.....when you multiply you add the exponents
5 0
2 years ago
Read 2 more answers
Explain why the product of a nonzero rational number and an irrational number is irrational
spayn [35]

Answer:

If you multiply any irrational number by the rational number zero, the result will be zero, which is rational. Any other situation, however, of a rational times an irrational will be irrational.

3 0
3 years ago
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