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3 years ago

Evaluate: 14/2 - 3 + 6/3

Mathematics

2 answers:

lora16 [44]3 years ago

6 0

Answer:

$6$

$\frac{14}{2?} - 3 + \frac{6}{3 ?} \\ 7 - 3 + \frac{6}{?3 } = 6 \\ 4 + \frac{6}{?3} = 6 \\ 4 + 2 = 6$

ozzi3 years ago

5 0

Answer:

Brainliest!!!

Step-by-step explanation:

see picture

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On Monday 172 students went on a trip to the zoo all 4 buses were filled and 9 students had to travel in cars.How many students

il63 [147K]

Answer:

Three was 43 students in each bus

Step-by-step explanation:

4 0

3 years ago

A communications tower is supported by two wires, connected at the same point on the ground. One is attached to the tower at D a

viktelen [127]

Answer:

10.99 m

Step-by-step explanation:

✍️What we are basically asked to solve here is to find the distance between C and D.

To find CD, find the length of BC, and BD. Their difference will give us CD.

Thus, BC - BD = CD.

✍️Finding BC using trigonometric ratio formula:

$\theta = 30 + 10 = 40$

Opposite side = BC = ??

Adjacent side = 42 m

Thus:

$tan(\theta) = \frac{opposite}{adjacent}$

Plug in the values

$tan(40) = \frac{BC}{42}$

Multiply both sides by 42

$tan(40) \times 42 = \frac{BC}{42} \times 42$

$35.24 = BC$

BC = 35.24 m

✍️Finding BD using trigonometric ratio formula:

$\theta = 30$

Opposite side = BD = ??

Adjacent side = 42 m

Thus:

$tan(\theta) = \frac{opposite}{adjacent}$

Plug in the values

$tan(30) = \frac{BD}{42}$

Multiply both sides by 42

$tan(30) \times 42 = \frac{BD}{42} \times 42$

$24.25 = BD$

BD = 24.25 m

✍️How much below the top of the tower is the shorter one attached:

Thus,

BC - BD = CD

35.24 m - 24.25 m = 10.99 m

7 0

3 years ago

Max and Emma are discussing their math homework and disagree on the answer for one question. Max says that integers are closed u

hram777 [196]

A set has closure under an operation if performance of that operation on members of the set always produces a member of the same set; in this case we also say that the set is closed under the operation.

A closure property is a certain rule that holds <u>if it is true for all elements of a set under the given operation</u> and a closure property does not hold <u>if there is at least one pair of elements that do not follow the closure property under the given operation.</u>

Therefore, Emma is correct, because you can find a counterexample (7:2=3.5) that gives you a non-integer answer.

Answer: correct option is B

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3 years ago

What other information do you need in order to prove the triangles

GuDViN [60]

Answer:

However, we need to know that segment AB is congruent to segment CD, in order to use SAS.

Hope it helps!

Step-by-step explanation:

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3 years ago

How do you determine where f(x)=cos^(-1)(lnx) is continuous?

olga nikolaevna [1]

$\ln x$ is continuous over its domain, all real $x>0$ .

Meanwhile, $\cos^{-1}y$ is defined for real $-1\le y\le1$ .

If $y=\ln x$ , then we have $-1\le \ln x\le1\implies \dfrac1e\le x\le e$ as the domain of $\cos^{-1}(\ln x)$ .

We know that if $f$ and $g$ are continuous functions, then so is the composite function $f\circ g$ .

Both $\cos^{-1}y$ and $\ln x$ are continuous on their domains (excluding the endpoints in the case of $\cos^{-1}y$ ), which means $\cos^{-1}(\ln x)$ is continuous over $\dfrac1e$ .

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3 years ago