Question

Can someone please help with NUMBER 7?!! It’s my last one I will mark brainliest to the best answer

Answer 1

Answer:

1, 3, 9, 27

Step-by-step explanation:

$a_n = 3^{n - 1}$

You need the first 4 terms, so let n = 1, and evaluate the expression. Then do the same for n = 2, n = 3, and finally n = 4.

n = 1

$a_1 = 3^{1 - 1} = 3^0 = 1$

n = 2

$a_2 = 3^{2 - 1} = 3^1 = 3$

n = 3

$a_3 = 3^{3 - 1} = 3^2 = 9$

n = 4

$a_4 = 3^{4 - 1} = 3^3 = 27$