B.225/20 =11.25 prr hour
a.225/20=h
Answer:
Mean: 


Step-by-step explanation:
Given
See attachment for data
Solving (a): The mean
Mean is calculated as:

From the attached:

So, the mean is:



Solving (b): The median
; this is an even number. So, the median is:




This implies that the median is the average of the 7th and 8th item.
Next, is to order the data (in ascending order): <em>36.45, 38.03, 38.19, 39.17, 39.44, 40.1, 40.2, 40.2, 40.3, 43.1, 43.2, 43.4, 43.4, 43.4.</em>
The 7th and 8th items are: 40.2 and 40.2
The median is:



Solving (c): The mode
43.4 has the highest number of occurrence.
So:

Answer:
Step-by-step explanation:
let the smaller square be A, and the side is a
larger square is B, the side is a+3
Area(A)=a^2
Area(B)=(a+3)^2
a^2+(a+3)^2=425 in^2
a^2+a^2+6a+9=425
2a^2+6a=425-9
2(a^2+3a)=416 we divide by 2
a^2+3a=208
we solve the quadratic function
we will get two roots, a(1)=13, and the negative answer we will ignore
a=13 and the side of the larger square is 13+3=16
The line is parallel to the bisector of the 1st and 3rd quadrants

except it is shifted down 2 units:

Since we're considering the area below the graph (not included), the inequality is
