1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Citrus2011 [14]
3 years ago
5

What is the volume of the walls of the igloo?

Mathematics
1 answer:
Gnesinka [82]3 years ago
3 0
Volume= 2pie R^3
—————
3
You might be interested in
Which expression has the least value?<br> A. 3(33)<br> B. 0 31-33)<br> C. 0-31-33)<br> D. 3(3-3)
Deffense [45]

Answer:

I think it is C but can't be sure because B isn't clear.

Step-by-step explanation:

4 0
3 years ago
Is 5/10 equivalent to 1/6​
Citrus2011 [14]

Answer:

No, its not equivalent

1/2 is equivalent though

Please mark as brainliest

8 0
2 years ago
Read 2 more answers
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.&lt;b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
Which of the binomials below is a factor of this trinomial?<br> x^2- 14x+ 24
Ray Of Light [21]

Answer:

(x-2)(x-12)

Step-by-step explanation:

x^2-14x+24=(x-2)(x-12)

5 0
3 years ago
-7y - 3 - 2y= -5(y + 3)
Nana76 [90]

Answer:

y=-1(1)/(5)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Other questions:
  • Plz help ASAP matswatch
    9·1 answer
  • 26. Identify the property a+(b+c) = (b+c)+a *
    15·1 answer
  • Plz i need helpPlzzzzz I need help
    13·1 answer
  • Find side b if side a = 10 inches and side c = 16 inches.Round to the nearest hundredth if the answer is uneven
    9·1 answer
  • What is the solution to the equation? -6.8 + 2.6+ x = 9.7
    8·2 answers
  • A grocer is stocking cans of beans on his shelf for a 7-day week and will
    5·1 answer
  • This equation shows how the amount of money Sadie makes from selling lemonade is related to the number of cups sold. d =3c
    14·1 answer
  • Help please!!! LOOK AT IMAGE ATTACHED tysm for those who helped!! :)
    9·1 answer
  • Fill in the missing number.<br><br> __% of 80 = 60
    15·2 answers
  • What is three squared minus two thirds?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!