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3 years ago

What is five hundred six and twelve hundredths in standard form

Mathematics

1 answer:

Trava [24]3 years ago

5 0

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ Five hundred six and twelve hundredths in standard form is 506.12

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2/2 - 7x-4 Simplify - 58+4 2x + 1 2-1 2x + 1 *+1 2-72

Pachacha [2.7K]

Answer:

A or (2x+1)/(x-1)

Step-by-step explanation:

Let's simplify the top of the fraction first.

1. Simplify the numerator.

2x^2 -7x-4=(2x+1)(x-4)

2. Simplify the denominator.

x^2-5x+4=(x-4)(x-1)

Now we have:

((2x+1)(x-4))/((x-4)(x-1))

We see that there is an (x-4) both on the numerator and denominator.

We can remove (x-4) by division.

Doing that, we have:

(2x+1)/(x-1) or A

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4 years ago

A spinner is numbered 1 through 5 is spun 3 times. What is the probability of spinning a number less than 3, then a number great

Anarel [89]

For the first two,the probability is 0.4, and for # 3,the probability is .2

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4 years ago

Find dy/dx. x^2y+xy^2=6

AfilCa [17]

We are asked to evaluate dx/dy of the function x^2y+xy^2=6
we use implicit differentiation here:
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3 0

3 years ago

Consider F and C below. F(x, y, z) = 2xz + y2 i + 2xy j + x2 + 9z2 k C: x = t2, y = t + 3, z = 3t − 1, 0 ≤ t ≤ 1 (a) Find a func

Ray Of Light [21]

Answer:

a)∇f = 2y + 2x + 18z

b) $\int\limits^._C {F} \, dr$ =108

Step-by-step explanation:

Given:

f (x,y,z ) = $(2xz+ y^{2})i + (2xy) j +(x^{2} + 9z^{2})k$

The curve C :

$x=t^{2} ,\\y= t+3\\z= 3t-1$

where 0 ≤ t ≤ 1

Required:

(a) F = ∇f =? (F is a vector here)

(b) $\int\limits^._C {F} \, dr$ =?

Solution

First we will find the directional derivative F = ∇f

for that , we will use the formula :

∇f = $F_{x}i+ F_{y} j+F_{z}k$

Fx= δf/δx = δ/δx $(2xz+ y^{2})i$ = 2z i

Fy= δf/δy=δ/δy (2xy)j = 2x j

Fz= δf/δz=δ/δz $(x^{2} + 9z^{2})k$ = 18z k

∇f = (2z) i .i + (2x) j.j + (18z) k.k

∇f = 2z + 2x + 18z

For part b):

we will use line integral formula:

$\int\limits^._C {F} \, dr$

to calculate dr, we will need the curve C:

r = x(t)+y(t)+z(t)

r= $(t^{2})i + (t+3) j +(3t-1) k$

$\frac{dr}{dt}=\frac{dx}{dt} +\frac{dy}{dt} + \frac{dz}{dt}$

$\frac{dx}{dt} = 2t$

$\frac{dy}{dt} = 1$

$\frac{dz}{dt} = 3$

$\int\limits^._C {F} \, dr$ = $\int\limits^1_0 {F_{x} } \, dx+ F_{y} dy +F_{z} dz$

= $\int\limits^1_0 {(2z(2t) + 2x(1) + 18z (3)} \, )$

put values of y, x and z

= $\int\limits^1_0 {2(3t-1) + 2(t^{2}) +18 (3) (3t-1)} \,$

= ${2t^{2} + 6t+162t -54-2}\, |^1_0$

= ${ 2t^{2}+ 168t - 56} \,|^1_0$ (Note : f(1)-f(0))

=2(1)+162(1)+2(0)+162(0)-56

= 2+162 -56

$\int\limits^._C {F} \, dr$ =108

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3 years ago

An engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 3.6

Natali [406]

Answer:

She must consider 3507 components to be 90% sure of knowing the mean will be within ± 0.1 mm.

Step-by-step explanation:

We are given that an engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 3.6 mm.

And she considers to be 90% sure of knowing the mean will be within ±0.1 mm.

As we know that the margin of error is given by the following formula;

The margin of error = $Z_(_\frac{\alpha}{2}_) \times \frac{\sigma}{\sqrt{n} }$

Here, $\sigma$ = standard deviation = 3.6 mm

n = sample size of components

$\alpha$ = level of significance = 1 - 0.90 = 0.10 or 10%

$\frac{\alpha}{2} = \frac{0.10}{2}$ = 0.05 or 5%

Now, the critical value of z at a 5% level of significance in the z table is given to us as 1.645.

So, the margin of error = $Z_(_\frac{\alpha}{2}_) \times \frac{\sigma}{\sqrt{n} }$

0.1 mm = $1.645 \times \frac{3.6}{\sqrt{n} }$

$\sqrt{n} = \frac{3.6\times 1.645}{0.1 }$

$\sqrt{n}$ = 59.22

n = $59.22^{2}$ = 3507.0084 ≈ 3507.

Hence, she must consider 3507 components to be 90% sure of knowing the mean will be within ± 0.1 mm.

8 0

4 years ago