Jen wants to tile the floor of her kitchen. The floor is rectangular and measures 12 feet by 8 feet. If it costs $2.50 per squar
e foot for the materials, what is the total of the materials for tiling the kitchen floor?
1 answer:
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Check the picture below.
so the lunchbox is really a semi-circle with a radius of 3, sitting on top of a square of 6x6, with a lenght of 10.
the volume of the lunchbox then will be the area of the semi-circle and square times the length.
![\bf \left[ \stackrel{\textit{semi-circle's area}}{\frac{\pi 3^2}{2}}+\stackrel{\textit{square's area}}{(6\cdot 6)} \right]\stackrel{length}{10}\implies \left( \frac{9\pi }{2}+36\right)(10)](https://tex.z-dn.net/?f=%5Cbf%20%5Cleft%5B%20%5Cstackrel%7B%5Ctextit%7Bsemi-circle%27s%20area%7D%7D%7B%5Cfrac%7B%5Cpi%203%5E2%7D%7B2%7D%7D%2B%5Cstackrel%7B%5Ctextit%7Bsquare%27s%20area%7D%7D%7B%286%5Ccdot%206%29%7D%20%5Cright%5D%5Cstackrel%7Blength%7D%7B10%7D%5Cimplies%20%5Cleft%28%20%20%5Cfrac%7B9%5Cpi%20%7D%7B2%7D%2B36%5Cright%29%2810%29)
so the lunchbox is really a semi-circle with a radius of 3, sitting on top of a square of 6x6, with a lenght of 10.
the volume of the lunchbox then will be the area of the semi-circle and square times the length.
Answer:
Step-by-step explanation:
The idea here is to find the value for x and y, then add them together. See the pic I attached below. We will solve for side x first.
Side s is across from the reference angle of 48 degrees; side measuring 50 m is adjacent to the reference angle 48 degrees. Therefore, we will use the tangent ratio to solve for x:
and
50tan(48) = x so
x = 55.53m
Now we will do the same and solve for y. This time the reference angle is 28 degrees. Side y is opposite the reference angle and the side measuring 50 is adjacent to the reference angle, so we will use the tangent ratio again:
and
50tan(28) = y so
y = 26.59. Therefore,
x + y = 55.53 + 26.59 and
the height of the taller building is
82.1 m
