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3 years ago

What solves the equation? (Needs to be simplified)

Mathematics

1 answer:

Alja [10]3 years ago

8 0

$\bf \cfrac{4v+1}{6v^2-19v+10}\div \boxed{x}=\cfrac{4v-1}{3v-2}\implies \cfrac{~~\frac{4v+1}{6v^2-19v+10}~~}{x}=\cfrac{4v-1}{3v-2} \\\\\\ \stackrel{\textit{cross-multipying}}{\cfrac{~~\frac{4v+1}{6v^2-19v+10}~~}{\frac{4v-1}{3v-2}}=x}\implies \cfrac{4v+1}{6v^2-19v+10}\cdot \cfrac{3v-2}{4v-1}=x \\\\\\ \cfrac{4v+1}{(\underline{3v-2})(2v-5)}\cdot \cfrac{\underline{3v-2}}{4v-1}=x\implies \cfrac{4v+1}{(2v-5)(4v-1)}=x \\\\\\ \cfrac{4v+1}{8v^2-2v-20v+5}=x\implies \cfrac{4v+1}{8v^2-22v+5}=x$

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Let ABC be an isosceles triangle with AB = AC and ∠BAC=30°. Side AB and the median AD contain points Q and P respectively (point

juin [17]

Answer:

15°

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Step-by-step explanation:

Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)

The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.

Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.

Angle PQC is 15°.

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3 years ago

An architect designs a castle tower for a new attraction at a popular amusement park. Blueprints of the tower, which is in the s

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Answer:

The surface area of the tower is 5,218.1 m²

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Height of the blueprint = 47 cm

Length of the blueprint = 23 cm

Width of the blueprint = 25 cm

Scale factor 1 : 96

2. Calculate the actual surface area of the tower and enter your answer in square meters with two decimal places.

Let's calculate the measurements of the actual tower:

Height of the blueprint = 47 * 96 = 4,512 cm = 45.12 m

Length of the blueprint = 23 * 96 = 2,208 cm = 22.08 m

Width of the blueprint = 25 * 96 = 2,400 cm = 24 m

Now, let's calculate the surface area of the tower, this way:

Surface area of the tower = 2* (24 * 22.08) + 2 * (45.12 * 22.08) + 2 * (45.12 * 24)

Surface area of the tower = 1,059.84 + 1,992.5 + 2,165.76

Surface area of the tower = 5,218.1 m²

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4 years ago