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kirza4 [7]
3 years ago
5

What solves the equation? (Needs to be simplified)

Mathematics
1 answer:
Alja [10]3 years ago
8 0

\bf \cfrac{4v+1}{6v^2-19v+10}\div \boxed{x}=\cfrac{4v-1}{3v-2}\implies \cfrac{~~\frac{4v+1}{6v^2-19v+10}~~}{x}=\cfrac{4v-1}{3v-2} \\\\\\ \stackrel{\textit{cross-multipying}}{\cfrac{~~\frac{4v+1}{6v^2-19v+10}~~}{\frac{4v-1}{3v-2}}=x}\implies \cfrac{4v+1}{6v^2-19v+10}\cdot \cfrac{3v-2}{4v-1}=x \\\\\\ \cfrac{4v+1}{(\underline{3v-2})(2v-5)}\cdot \cfrac{\underline{3v-2}}{4v-1}=x\implies \cfrac{4v+1}{(2v-5)(4v-1)}=x \\\\\\ \cfrac{4v+1}{8v^2-2v-20v+5}=x\implies \cfrac{4v+1}{8v^2-22v+5}=x

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Hatshy [7]
183.26 times .25 = 45.815
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3 0
3 years ago
F(x)= -2x^2 - 5 and f(2)= -13<br><br> can someone solve this in steps please?
Rashid [163]

This is one way you could write out the steps

f(x) = -2x^2 - 5

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f(2) = -2(4) - 5

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4 0
2 years ago
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Korvikt [17]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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<span>b. 1</span>
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2 years ago
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fgiga [73]
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Hope this Helps! :)
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3 years ago
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