What solves the equation? (Needs to be simplified)

Mathematics

1 answer:

Alja [10]3 years ago

8 0

$\bf \cfrac{4v+1}{6v^2-19v+10}\div \boxed{x}=\cfrac{4v-1}{3v-2}\implies \cfrac{~~\frac{4v+1}{6v^2-19v+10}~~}{x}=\cfrac{4v-1}{3v-2} \\\\\\ \stackrel{\textit{cross-multipying}}{\cfrac{~~\frac{4v+1}{6v^2-19v+10}~~}{\frac{4v-1}{3v-2}}=x}\implies \cfrac{4v+1}{6v^2-19v+10}\cdot \cfrac{3v-2}{4v-1}=x \\\\\\ \cfrac{4v+1}{(\underline{3v-2})(2v-5)}\cdot \cfrac{\underline{3v-2}}{4v-1}=x\implies \cfrac{4v+1}{(2v-5)(4v-1)}=x \\\\\\ \cfrac{4v+1}{8v^2-2v-20v+5}=x\implies \cfrac{4v+1}{8v^2-22v+5}=x$

You might be interested in

What is the geometric mean of 8 and 10?

nekit [7.7K]

If the smaller number is x, then the larger number has to be 20 - x in order for the arithmetic mean to be 10, as their sum must be 20.

If the geometric mean is 8 the product of the numbers has to be 64 and so the larger number is 64/x

Solving 64/x = 20 - x gives the quadratic x^2 -20x +64 = 0 so x = 4 or 16.

The two numbers are 4 and 16.

3 0

2 years ago

Read 2 more answers

Describe the effects of translating abc abc

aleksklad [387]

Answer:

If you meant describe the effects of translating Δ ABC to Δ A'B'C'.

D. Each x - coordinate decreased by 6 and each y - coordinate increased by

Use the coordinate A as an example it moves to the right 6 times(x increasing) and down 3 times (y decreasing)