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balandron [24]
3 years ago
12

35 2/9 divided 5 8/9

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

53/405

Step-by-step explanation:

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Answer:

0

Step-by-step explanation:

y2-y1/x2-x1

-2+2/3-0

0/3

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Step-by-step explanation:

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4 0
3 years ago
Assume that different groups of couples use the XSORT method of gender selection and each couple gives birth to one baby. The XS
olganol [36]

Answer:

Mean and Standard deviation for the numbers of girls in groups of 36 births are 18 and 3 respectively.

Step-by-step explanation:

We are given that he X SORT method is designed to increase the likelihood that a baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5.

Now consider a group consisting of 36 couples.

The above situation can be represented through binomial distribution;

P(X=r)=\binom{n}{r} \times p^{r} \times (1-p)^{n-r} ;x=0,1,2,3,.....

where, n = number of trials (samples) taken = 36 couples

            r = number of success

            p = probability of success which in our question is probability

                   of a girl, i.e.; p = 0.5

<em><u>Let X = Numbers of girls in groups of 36 births </u></em>

So, X ~ Binom(n = 36, p = 0.5)

Now, mean for the numbers of girls in groups of 36 births is given by;

         <u>Mean</u>, E(X) = n \times p = 36 \times 0.5 = 18

Also, standard deviation for the numbers of girls in groups of 36 births is given by;

        <u>Standard deviation</u>, S.D.(X) =  \sqrt{n\times p\times (1-p)}

                                                      =  \sqrt{36\times 0.5\times (1-0.5)}

                                                      =  3

3 0
3 years ago
Find the quotient 5 68
kobusy [5.1K]
The quotient is 13.6
8 0
3 years ago
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