First, we need to simplify your quadratic equation, in the form of ax^2-bx-c=0. Your equation turns out to be x^2-4x+5=0 To find your solutions, x1+x2=-b/a or 4 in this case, and x1*x2=c/a or 5 in this case. So we need to find two numbers when added together is 4 and multiplied together to get 5. We can easily find our roots by using the roots formula, or (-b (+/-)sqrt(b^2-4ac))/2a. When plugging everything in, we have (4(+/-)sqrt(16-20)/2. As you can make out from the plugged in equation, you can't have a negative number under the radical symbol in order for it to be true. Your answer is C, no real solutions. Hope this helps.
