1-3 are about trigonometric ratios (SOH CAH TOA). 4, 5 are about the Law of Cosines, and 6 uses the Law of Sines.
1. Sin = Opposite/Hypotenuse
x = 10*sin(40°) ≈ 6.428
2. Sin = Opposite/Hypotenuse
x = arcsin(7/12) ≈ 35.69°
3. Tan = Opposite/Adjacent
x = 18/tan(52°) ≈ 14.063
4. b^2 = a^2 +c^2 -2ac*cos(B)
B = arccos((a^2 +c^2 -b^2)/(2ac)) = arccos((7^2 +13^2 -8^2)/(2*7*13))
B = arccos(11/13) ≈32.20°
5. Same formula.
x = √(a^2 +c^2 -2ab*cos(B)) = √(157-132cos(42°)) ≈ 7.675
6. The ratio of side lengths is the same as the ratio of the sines of the opposite angles.
6/10 = sin(x)/sin(100°)
x = arcsin((6/10)*sin(100°)) ≈ 36.22°
Y=mx+b which therefore is 4x+7
Answer:
So if Keven started with 0 he then got 6 then gave it away, that means he simply had none to himself.
Answer:
is it from a text book
Step-by-step explanation:
Answer:
17 units
Step-by-step explanation:
Given 2 congruent chords in the circle, then they are equidistant from the centre and perpendicular
There is a right triangle formed by legs 15 and 8, with radius r being the hypotenuse.
Using Pythagoras' identity in this right angle
r² = 15² + 8² = 225 + 64 = 289 ( take the square root of both sides )
r = 
= 17
