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3 years ago

Need help simplifying, (-6√80)(3)

Mathematics

1 answer:

svlad2 [7]3 years ago

3 0

-72\sqrt(5) this is the answer i did all my math and i got this answer

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The ratio of the measure of three angles of a triangle is 2:3:10. Find the measure of the largest angle.

faltersainse [42]

Answer:

The measure of the largest angle:

120°

Step-by-step explanation:

The sum of the internal angles of a triangle = 180°:

2 + 3 + 10 = 15

then:

180/15 = 12

then, the measure of the largest angle:

10 * 12 = 120°

5 0

3 years ago

Read 2 more answers

Estimate the answer to 28.56 – 15.98 by first rounding each number to the nearest whole number. A. 13 B. 12.7 C. 12 D. 10

Scorpion4ik [409]

The answer is 12.58 rounded up it would be 13 so the correct answer is A

6 0

3 years ago

Read 2 more answers

Sums of series, Maths. Any help appreciated.

Andrej [43]

Answer:

Step-by-step explanation:

Well, a series in math is simply the sum of the various numbers, or elements of a sequence. For example, to make a series from the sequence of the first five positive integers 1, 2, 3, 4, 5, just add them up. So, 1 + 2 + 3 + 4 + 5 = 15 is a series.

that all what i know i am really sorry bro but that is what i understand !

7 0

3 years ago

A firework is launched from the ground at a velocity of 180 feet per second. its height after t (t is variable) seconds is given

VMariaS [17]

-16t² + 180t

-16(2)² + 180(2)

-64 + 360

The fireworks height after 2 seconds is 296 feet

7 0

2 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

3 years ago