What are the prime factors of 625?
2 answers:
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Answer:
x = - 3, x =
Step-by-step explanation:
Given
4x² + 2x - 30 = 0 ( divide through by 2 )
2x² + x - 15 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 15 = - 30 and sum = + 1
The factors are + 6 and - 5
Use these factors to split the x- term
2x² + 6x - 5x - 15 = 0 ( factor the first/second and third/fourth terms )
2x(x + 3) - 5(x + 3) = 0 ← factor out (x + 3) from each term
(x + 3)(2x - 5) = 0
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
2x - 5 = 0 ⇒ 2x = 5 ⇒ x =