State three factors that determine a torque.
1 answer:
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Answer: = 16.49N
Explanation: The object is placed on an inclined plane at an angle of 37° thus making it weight have two component,
= horizontal component of the weight = mgsinФ
= vertical component of weight = mgcosФ
Due to the way the object is positioned, the horizontal component of force will accelerate the object thus acting as an applied force.
by using newton's law of motion, we have that
mgsinФ - = ma
where m = mass of object=5kg
a = acceleration= unknown
Ф = angle of inclination = 37°
g = acceleration due to gravity = 9.8
= frictional force = unknown
we need to first get the acceleration before the frictional force which is gotten by using the equation below
where v = final velocity = 2m/s
u = initial velocity = 0m/s (because the object started from rest)
a= unknown
S= distance covered = length of plane = 5m
we slot in a into the equation below to get frictional force
mgsinФ - = ma
3 * 9.8 * sin 37 - = 3* 0.4
17.9633 - = 1.2
= 17.9633 - 1.2
= 16.49N
Answer: 24.24 m
Explanation:
A player throws football 50.0 m at 61° North of west. we will write this in terms of horizontal and vertical components.
Horizontal component: 50 cos 61° = 24.24 m which is westwards
Vertical component: 50 sin 61° = 43.73 m which towards North.
Refer to diagram below.
Thus, the westward component of displacement of the football is the horizontal component of the displacement = 24.24 m.
